EP ESSENTIAL ORG.CHEM.-MOD.MASTERING
EP ESSENTIAL ORG.CHEM.-MOD.MASTERING
3rd Edition
ISBN: 9780133858501
Author: Bruice
Publisher: PEARSON CO
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Chapter 13, Problem 48P
Interpretation Introduction

Interpretation: Reason behind the formation of acetone containing 18O when enzymatic decarboxylation of acetoacetate is carried out in H218O has to be stated.

Concept introduction: Decarboxylation of acetoacetate is initiated by an enzyme named acetoacetate decarboxylase. Enzyme forms protonate imine with substrate acetoacetate. It loses carbondioxide in presence of a H218O to form an enamine. The reaction proceeds further and undergoes hydrolysis to regenerate the enzyme.

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A graduate student was studying enzymatic reductions of cyclohexanones when she encountered some interesting chemistry. When she used an enzyme and NADPH to reduce the following ketone, she was surprised to find that the product was optically active. She carefully repurified the product so that no enzyme, NADPH, or other contaminants were present. Still, the product was optically active. If this reaction could be accomplished using H2 and a nickel catalyst, would the product be optically active? Explain.
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Which of the following bases are strong enough to deprotonate C6H5OH(pKa = 10) so that equilibrium favors the products:(a) H2O; (b) NaOH; (c) NaNH2; (d) CH3NH2; (e) NaHCO3; (f) NaSH; (g)NaH?
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