Chapter 13, Problem 44QRT

(a)

Interpretation Introduction

Interpretation:

The mass of ${\text{NH}}_{\text{4}}\text{Cl}$ needed to prepare $\text{750}\text{mL}\text{of }\text{4}\text{.00}\text{M}$${\text{NH}}_{\text{4}}\text{Cl}$ has to be calculated.

Concept Introduction:

Molarity (M): Molarity is number of moles of the solute present in the one liter of the solution.

  $\text{Molarity}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Volume of solution in L}}.$

The number of moles of any substance can be determined using the equation

  $\text{Number}\text{of}\text{moles}\text{=}\frac{\text{Given}\text{mass}\text{of}\text{the}\text{substance}}{\text{Molar}\text{mass}}.$

Moles: One mole is equivalent to the mass of the substance consists of same number of units equal to the atoms present in $\text{12}\text{g}$ of ${}^{\text{12}}\text{C}$.

(b)

Interpretation Introduction

Interpretation:

The mass of $\text{KCl}$ needed to prepare $\text{1}\text{.50}\text{L}\text{of }\text{0}\text{.750}\text{M}$$\text{KCl}$ has to be calculated.

Concept introduction:

Refer part (a).

(c)

Interpretation Introduction

Interpretation:

The mass of ${\text{Na}}_{\text{2}}{\text{SO}}_{\text{4}}$ needed to prepare $\text{150}\text{mL}\text{of }\text{0}\text{.350}\text{M}$${\text{Na}}_{\text{2}}{\text{SO}}_{\text{4}}$ has to be calculated.

Concept Introduction:

Refer to part (a).