Chemistry for Changing Times
Chemistry for Changing Times
14th Edition
ISBN: 9780134212777
Author: John W. Hill; Terry W. McCreary
Publisher: Pearson Education (US)
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Chapter 13, Problem 40P
Interpretation Introduction

Interpretation: The relation between free radicals and ozone layer should be explained.

Concept Introduction: Free radicals are reactive due to presence of an unpaired electron on them. They can combine with other free radicals to form stable molecule. They can also react with stable molecules to convert them into free radicals. They are responsible for initiation of many chemical reactions.

Ozone molecule contains 3 atoms of oxygen. It forms a protective layer on atmosphere in the stratosphere.

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The reaction for obtaining NO2 from NO and O2 has the rate equation: v = k[NO]2[O2]. Indicate which of the following options is correct.(A). This rate equation is inconsistent with the reaction consisting of a single trimolecular step.(B). Since the overall order is 3, the reaction must necessarily have some trimolecular step in its mechanism.(C). A two-step mechanism:  1) NO + NO ⇄ N2O2 (fast);   2) N2O2 + O2 → NO2 + NO2 (slow).(D). The mechanism must necessarily consist of three unimolecular elementary steps with very similar rate constants.
a. What is the eluent used in the column chromatography here (a “silica plug filtration” is essentially a very short column)? b. The spectroscopy of compound 5b is described in the second half of this excerpt, including 1H-NMR and 13C-NMR (which you will learn about in CHEM 2412L), MS (which you will learn about later in CHEM 2411L) and IR. One of the IR signals is at 3530 cm-1. What functional group does this indicate might be present in compound 5b?
Steps and explanations. Also provide, if possible, ways to adress this kind of problems in general.

Chapter 13 Solutions

Chemistry for Changing Times

Ch. 13 - Prob. 11PCh. 13 - Prob. 12PCh. 13 - Prob. 13PCh. 13 - Prob. 14PCh. 13 - Prob. 15PCh. 13 - Prob. 16PCh. 13 - Prob. 17PCh. 13 - Prob. 18PCh. 13 - For Problems 19-22, write the balanced equation...Ch. 13 - For Problems 19-22, write the balanced equation...Ch. 13 - Prob. 21PCh. 13 - For Problems 19-22, write the balanced equation...Ch. 13 - Prob. 23PCh. 13 - Prob. 24PCh. 13 - Prob. 25PCh. 13 - Prob. 26PCh. 13 - Prob. 27PCh. 13 - Describe two ways in which the level of nitrogen...Ch. 13 - Prob. 29PCh. 13 - Prob. 30PCh. 13 - Prob. 31PCh. 13 - Prob. 32PCh. 13 - Prob. 33PCh. 13 - Prob. 34PCh. 13 - Prob. 35PCh. 13 - Prob. 36PCh. 13 - Prob. 37PCh. 13 - Prob. 38PCh. 13 - Prob. 39PCh. 13 - Prob. 40PCh. 13 - Prob. 41PCh. 13 - Prob. 42PCh. 13 - Prob. 43PCh. 13 - Prob. 44PCh. 13 - Prob. 45PCh. 13 - Prob. 46PCh. 13 - Prob. 47PCh. 13 - Prob. 48PCh. 13 - Prob. 49PCh. 13 - Prob. 50PCh. 13 - Prob. 51PCh. 13 - 52. What kind of particulate matter is often found...Ch. 13 - Prob. 53PCh. 13 - Prob. 54PCh. 13 - Prob. 55PCh. 13 - Prob. 56PCh. 13 - Prob. 57PCh. 13 - Prob. 58PCh. 13 - Prob. 59APCh. 13 - Prob. 60APCh. 13 - Prob. 61APCh. 13 - Prob. 62APCh. 13 - Prob. 63APCh. 13 - Prob. 64APCh. 13 - Prob. 65APCh. 13 - Prob. 66APCh. 13 - Prob. 67APCh. 13 - Although carbon dioxide is the actual greenhouse...Ch. 13 - Prob. 69APCh. 13 - Explain why a thermal inversion causes pollution...Ch. 13 - The specific heat of a substance is the amount of...Ch. 13 - Prob. 72APCh. 13 - Prob. 73APCh. 13 - Which of the following components is not recycled...Ch. 13 - Prob. 13.1CTECh. 13 - Prob. 13.2CTECh. 13 - Prob. 13.3CTECh. 13 - Prob. 13.4CTECh. 13 - Prob. 13.5CTECh. 13 - Prob. 13.6CTECh. 13 - Prob. 1CGPCh. 13 - Prob. 2CGPCh. 13 - Prob. 3CGPCh. 13 - Prob. 4CGPCh. 13 - Prob. 5CGPCh. 13 - Prob. 6CGPCh. 13 - Prob. 7CGPCh. 13 - Prob. 8CGPCh. 13 - Prob. 1CHQCh. 13 - Prob. 2CHQCh. 13 - Prob. 3CHQ
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