(a)
Interpretation:
The number of chlorination product obtained from radical chlorination of methylcyclohexane has to be given.
Concept introduction:
Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.
Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.
Chlorination:
2-methylpropane undergoes radical chlorination which yields the 2-chloro-2-methylpropane and 1-chloro-2-methylpropane.
(b)
Interpretation:
The product obtained in greater yield should be given and explained.
Concept introduction:
Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.
Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.
Chlorination:
2-methylpropane undergoes radical chlorination which yields the 2-chloro-2-methylpropane and 1-chloro-2-methylpropane.
(c)
Interpretation:
The number of monochlorination products obtained by considering all stereoisomers should be given.
Concept introduction:
Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.
Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.
Chlorination:
2-methylpropane undergoes radical chlorination which yields the 2-chloro-2-methylpropane and 1-chloro-2-methylpropane.
Chiral: Four different atoms attached to a carbon atom is called chiral molecule.
Stereoisomers: Stereoisomers are molecules that have the same molecular formula and they differ only in arrangement of atom in three-dimensional space.
Enantiomers: A compound which is non-superimposable mirror image is called enantiomers.
Diastereomers: A compound which is non-superimposable and non-mirror image is called enantiomers
Racemic mixture: A racemic mixture is simply a mixture containing an equal amount of each enantiomer

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Chapter 13 Solutions
EBK ORGANIC CHEMISTRY
- Use the Henderson-Hasselbalch equation to calculate pH of a buffer containing 0.050M benzoic acidand 0.150M sodium benzoate. The Ka of benzoic acid is 6.5 x 10-5arrow_forwardA. Draw the structure of each of the following alcohols. Then draw and name the product you would expect to produce by the oxidation of each. a. 4-Methyl-2-heptanol b. 3,4-Dimethyl-1-pentanol c. 4-Ethyl-2-heptanol d. 5,7-Dichloro-3-heptanolarrow_forwardWhat is the pH of a 1.0 L buffer made with 0.300 mol of HF (Ka = 6.8 × 10⁻⁴) and 0.200 mol of NaF to which 0.160 mol of NaOH were added?arrow_forward
- Can I please get help with this.arrow_forwardDetermine if the following salt is neutral, acidic or basic. If acidic or basic, write the appropriate equilibrium equation for the acid or base that exists when the salt is dissolved in aqueous solution. If neutral, simply write only NR. Be sure to include the proper phases for all species within the reaction. N₂H₅ClO₄arrow_forwardPlease help me with identifying these.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning

