Structures of four β − keto ester that is obtained from the mixture of methyl acetate and methyl propanoate have to be drawn. Concept Introduction: Reaction of an ester having an α − hydrogen with one equivalent of a base to yield a β − keto ester. Mechanism for Claisen Condensation: A base abstracts a proton from the α − c a r b o n forms enolate ion. The enolate ion gets attached to the carbonyl carbon of another ester. The negative charge on oxygen of the carbonyl group reforms, by removing an alkoxide ion.

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Answer 1

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Chapter 13, Problem 30P

Interpretation Introduction

Interpretation:

Structures of four β− keto ester that is obtained from the mixture of methyl acetate and methyl propanoate have to be drawn.

Concept Introduction:

Reaction of an ester having an α− hydrogen with one equivalent of a base to yield a β− keto ester.

Mechanism for Claisen Condensation:

A base abstracts a proton from the α−carbon forms enolate ion.

The enolate ion gets attached to the carbonyl carbon of another ester.

The negative charge on oxygen of the carbonyl group reforms, by removing an alkoxide ion.

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Answer 2

Question

Chapter 13, Problem 30P

Interpretation Introduction

Interpretation:

Structures of four β− keto ester that is obtained from the mixture of methyl acetate and methyl propanoate have to be drawn.

Concept Introduction:

Reaction of an ester having an α− hydrogen with one equivalent of a base to yield a β− keto ester.

Mechanism for Claisen Condensation:

A base abstracts a proton from the α−carbon forms enolate ion.

The enolate ion gets attached to the carbonyl carbon of another ester.

The negative charge on oxygen of the carbonyl group reforms, by removing an alkoxide ion.

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Check out a sample textbook solution

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Answer 3

Question

Chapter 13, Problem 30P

Interpretation Introduction

Interpretation:

Structures of four β− keto ester that is obtained from the mixture of methyl acetate and methyl propanoate have to be drawn.

Concept Introduction:

Reaction of an ester having an α− hydrogen with one equivalent of a base to yield a β− keto ester.

Mechanism for Claisen Condensation:

A base abstracts a proton from the α−carbon forms enolate ion.

The enolate ion gets attached to the carbonyl carbon of another ester.

The negative charge on oxygen of the carbonyl group reforms, by removing an alkoxide ion.

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Answer 4

Question

Chapter 13, Problem 30P

Interpretation Introduction

Interpretation:

Structures of four β− keto ester that is obtained from the mixture of methyl acetate and methyl propanoate have to be drawn.

Concept Introduction:

Reaction of an ester having an α− hydrogen with one equivalent of a base to yield a β− keto ester.

Mechanism for Claisen Condensation:

A base abstracts a proton from the α−carbon forms enolate ion.

The enolate ion gets attached to the carbonyl carbon of another ester.

The negative charge on oxygen of the carbonyl group reforms, by removing an alkoxide ion.

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Answer 5

Chapter 13, Problem 30P

Interpretation Introduction

Interpretation:

Structures of four β− keto ester that is obtained from the mixture of methyl acetate and methyl propanoate have to be drawn.

Concept Introduction:

Reaction of an ester having an α− hydrogen with one equivalent of a base to yield a β− keto ester.

Mechanism for Claisen Condensation:

A base abstracts a proton from the α−carbon forms enolate ion.

The enolate ion gets attached to the carbonyl carbon of another ester.

The negative charge on oxygen of the carbonyl group reforms, by removing an alkoxide ion.

Answer 6

Chapter 13, Problem 30P

Interpretation Introduction

Interpretation:

Structures of four β− keto ester that is obtained from the mixture of methyl acetate and methyl propanoate have to be drawn.

Concept Introduction:

Reaction of an ester having an α− hydrogen with one equivalent of a base to yield a β− keto ester.

Mechanism for Claisen Condensation:

A base abstracts a proton from the α−carbon forms enolate ion.

The enolate ion gets attached to the carbonyl carbon of another ester.

The negative charge on oxygen of the carbonyl group reforms, by removing an alkoxide ion.

Answer 7

Chapter 13, Problem 30P

Interpretation Introduction

Interpretation:

Structures of four β− keto ester that is obtained from the mixture of methyl acetate and methyl propanoate have to be drawn.

Concept Introduction:

Reaction of an ester having an α− hydrogen with one equivalent of a base to yield a β− keto ester.

Mechanism for Claisen Condensation:

A base abstracts a proton from the α−carbon forms enolate ion.

The enolate ion gets attached to the carbonyl carbon of another ester.

The negative charge on oxygen of the carbonyl group reforms, by removing an alkoxide ion.

Answer 8

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Answer 11

Ch. 13.1 - Identify the most acidic hydrogen in each...Ch. 13.1 - Prob. 2P Ch. 13.1 - Prob. 3P Ch. 13.1 - Prob. 4P Ch. 13.1 - Explain why HO cannot remove a proton from the...Ch. 13.2 - Prob. 6P Ch. 13.2 - Prob. 7P Ch. 13.3 - Prob. 8P Ch. 13.3 - Prob. 9P Ch. 13.3 - Prob. 10P

Solution Summary: The author explains the structure of four beta - keto ester that is obtained from the mixture of methyl acetate

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