Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
10th Edition
ISBN: 9780073398204
Author: Richard G Budynas, Keith J Nisbett
Publisher: McGraw-Hill Education
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Chapter 13, Problem 20P
A compound reverted gear trains are to be designed as a speed increaser to provide a total increase of speed of exactly 45 to 1. With a 20° pressure angle, specify appropriate numbers of teeth to minimize the gearbox size while avoiding the interference problem in the teeth. Assume all gears will have the same diameter pitch.
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A compound reverted gear train is to be designed as a speed increaser to provide a total increase
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Chapter 13 Solutions
Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
Ch. 13 - A 17-tooth spur pinion has a diametral pitch of 8...Ch. 13 - A 15-tooth spur pinion has a module of 3 mm and...Ch. 13 - A spur gearset has a module of 6 mm and a velocity...Ch. 13 - A 21-tooth spur pinion mates with a 28-tooth gear....Ch. 13 - A 20 straight-tooth bevel pinion having 14 teeth...Ch. 13 - A parallel helical gearset uses a 20-tooth pinion...Ch. 13 - A parallel helical gearset consists of a 19-tooth...Ch. 13 - To avoid the problem of interference in a pair of...Ch. 13 - Prob. 9PCh. 13 - Prob. 10P
Ch. 13 - Prob. 11PCh. 13 - Prob. 12PCh. 13 - Prob. 13PCh. 13 - Prob. 14PCh. 13 - A parallel-shaft gearset consists of an 18-tooth...Ch. 13 - The double-reduction helical gearset shown in the...Ch. 13 - Shaft a in the figure rotates at 600 rev/min in...Ch. 13 - The mechanism train shown consists of an...Ch. 13 - The figure shows a gear train consisting of a pair...Ch. 13 - A compound reverted gear trains are to be designed...Ch. 13 - Prob. 21PCh. 13 - Prob. 22PCh. 13 - Prob. 23PCh. 13 - A gearbox is to be designed with a compound...Ch. 13 - The tooth numbers for the automotive differential...Ch. 13 - Prob. 26PCh. 13 - In the reverted planetary train illustrated, find...Ch. 13 - Prob. 28PCh. 13 - Tooth numbers for the gear train shown in the...Ch. 13 - The tooth numbers for the gear train illustrated...Ch. 13 - Shaft a in the figure has a power input of 75 kW...Ch. 13 - The 24T 6-pitch 20 pinion 2 shown in the figure...Ch. 13 - The gears shown in the figure have a module of 12...Ch. 13 - The figure shows a pair of shaft-mounted spur...Ch. 13 - Prob. 35PCh. 13 - Prob. 36PCh. 13 - A speed-reducer gearbox containing a compound...Ch. 13 - For the countershaft in Prob. 3-72, p. 152, assume...Ch. 13 - Prob. 39PCh. 13 - Prob. 40PCh. 13 - Prob. 41PCh. 13 - Prob. 42PCh. 13 - The figure shows a 16T 20 straight bevel pinion...Ch. 13 - The figure shows a 10 diametral pitch 18-tooth 20...Ch. 13 - Prob. 45PCh. 13 - The gears shown in the figure have a normal...Ch. 13 - Prob. 47PCh. 13 - Prob. 48PCh. 13 - Prob. 49PCh. 13 - The figure shows a double-reduction helical...Ch. 13 - A right-hand single-tooth hardened-steel (hardness...Ch. 13 - The hub diameter and projection for the gear of...Ch. 13 - A 2-tooth left-hand worm transmits 34 hp at 600...
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- Kindly help?arrow_forwardIf you don't know the solution please leave it for other expert.arrow_forwardCan someone help please. Thanks. Devise a gear train for a machine system with the following data. Input speed ni = 2500 rpm and the output speed must be between 90 rpm and 110 rpm. Use 20 o , full depth, involute teeth with diametral pitch Pd = 28. All the pinions should have exact number of teeth NP = 18 and the gear diameters should not exceed DG = 2.0 in. In your solution use the equal reduction ratio approach. 6arrow_forward
- Two straight-toothed bevel gears mesh with a shaft angle of 90° and a diametral pitch of 5. The pinion has 20 teeth, and the gear ratio is 2:1. The addendum and dedendum are the same as for 20 stub teeth. For the gear, determine the pitch radius, cone angle, outside diameter, cone distance, and face width.arrow_forwardUsing the most compact design without gear tooth interference, determine the number of teeth and stages to produce a speed reduction of 42:1. Sketch the train and label each gear and its number of teeth. Assume a 25° pressure angle, full tooth.arrow_forwardTo avoid the problem of interference in a pair of spur gears using a 20° pressure angle, specify the minimum number of tecth allowed on the pinion for each of the following gear ratios. (a) 2 to 1 (b) 3 to 1 (c) 4 to 1 (d) 5 to 1arrow_forward
- Urgent plzzarrow_forwardQ: Two involute gears having module 3 mm and pressure angle 20° mesh externally to give a velocity ratio of 3. For this mechanism, the pinion runs at 75 rpm and addendum is equal to one module.For these condetions compute: 1- The number of teeth on each gear so that interference is just avoided. 2- The length of path and arc of contact. 3- The number of pairs of teeth in contact. 4- The maximum value of sliding velocity. 5- If the transmitted power is 5 kW, what is the applied torque on pinion and wheel.arrow_forwardTwo spur gears are to have a ratio of 9:3 and a 7mm module. If the center distance is to be approximatively 200mm, calculate the following:o Circular pitch value;o Number of teeth on the wheel (gear);o Number of teeth of the pinion;arrow_forward
- Required information A gearbox with a compound reverted gear train transmits 25 horsepower with an input speed of 2500 rev/min. Spur gears with a diametral pitch of 4 teeth/in anda 20° pressure angle are used with 15 teeth on the each of the small gears and 44 teeth on each of the larger gears. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Determine the output torque, neglecting frictional losses. The output torque To is Ibf-in.arrow_forwardA gearset has the following parameters: diametral pitch = 8, pressure angle = 20°, 19-tooth pinion meshed with 37-tooth gear. Find the gear ratio, circular pitch, base pitch, pitch diameters, center distance, addendum, dedendum, whole depth, clearance, and the outside diameters.arrow_forwardFind the diameter of each gear using one simple gear train with 4 gears that work as a speed reducer with a ratio of 5:1 Input of 100 rpm, Output of 20 rpm. Consider number of teeth as: N1=20 N2=40 N3=80 N4=100 Use module of 2arrow_forward
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