Pentane is one of the most volatile of the hydrocarbons in gasoline. At 298.15 K, the following enthalpies of formation are given for pentane: Δ t H ° [ C z H 12 ( 1 ) ] = − 173.5 kJ mol − 1 ; Δ t H ° [ C z H 12 ( g ) ] = − 146.9 kJ Estimate the normal boiling point of pentane. Estimate Δ T G ° for pentane at 298 K. Comment on the significance of the sign of Δ v a c G ° for pentane at 298 K.
Pentane is one of the most volatile of the hydrocarbons in gasoline. At 298.15 K, the following enthalpies of formation are given for pentane: Δ t H ° [ C z H 12 ( 1 ) ] = − 173.5 kJ mol − 1 ; Δ t H ° [ C z H 12 ( g ) ] = − 146.9 kJ Estimate the normal boiling point of pentane. Estimate Δ T G ° for pentane at 298 K. Comment on the significance of the sign of Δ v a c G ° for pentane at 298 K.
Solution Summary: The author explains that the normal boiling point of pentane should be predicted. The standard enthalpy for a reaction is calculated by the formula.
Pentane is one of the most volatile of the hydrocarbons in gasoline. At 298.15 K, the following enthalpies of formation are given for pentane:
Δ
t
H
°
[
C
z
H
12
(
1
)
]
=
−
173.5
kJ
mol
−
1
;
Δ
t
H
°
[
C
z
H
12
(
g
)
]
=
−
146.9
kJ
Estimate the normal boiling point of pentane.
Estimate
Δ
T
G
°
for pentane at 298 K.
Comment on the significance of the sign of
Δ
v
a
c
G
°
for pentane at 298 K.
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