General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card)
General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card)
7th Edition
ISBN: 9781305253070
Author: STOKER, H. Stephen
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 13, Problem 13.53EP

(a)

Interpretation Introduction

Interpretation:

For the given molecule, whether cis‑trans isomerism is possible has to be indicated.

Concept Introduction:

Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.

A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.

A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.

Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.

Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

(b)

Interpretation Introduction

Interpretation:

For the given molecule, whether cis‑trans isomerism is possible has to be indicated.

Concept Introduction:

Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.

A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.

A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.

Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.

Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

(c)

Interpretation Introduction

Interpretation:

For the given molecule, whether cis‑trans isomerism is possible has to be indicated.

Concept Introduction:

Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.

A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.

A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.

Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.

Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

(d)

Interpretation Introduction

Interpretation:

For the given molecule, whether cis‑trans isomerism is possible has to be indicated.

Concept Introduction:

Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.

A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.

A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.

Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.

Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

Blurred answer
Students have asked these similar questions
Draw the product of the reaction shown below. Ignore inorganic byproducts. H conc. HBr Drawing Q
Calculate the atomic packing factor of diamond knowing that the number of Si atoms per cm3 is 2.66·1022 and that the atomic radii of silicon and oxygen are, respectively, 0.038 and 0.117 nm.
A pdf file of your hand drawn, stepwise mechanisms for the reactions. For each reaction in the assignment, you must write each mechanism three times (there are 10 reactions, so 30 mechanisms). (A) do the work on a tablet and save as a pdf., it is expected to write each mechanism out and NOT copy and paste the mechanism after writing it just once. Everything should be drawn out stepwise and every bond that is formed and broken in the process of the reaction, and is expected to see all relevant lone pair electrons and curved arrows. Aldol: NaOH HO H Δ NaOH Δ

Chapter 13 Solutions

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card)

Ch. 13.3 - Prob. 4QQCh. 13.4 - Prob. 1QQCh. 13.4 - Prob. 2QQCh. 13.5 - Prob. 1QQCh. 13.5 - Prob. 2QQCh. 13.5 - Prob. 3QQCh. 13.6 - Prob. 1QQCh. 13.6 - Prob. 2QQCh. 13.6 - Prob. 3QQCh. 13.7 - Prob. 1QQCh. 13.7 - Prob. 2QQCh. 13.7 - Prob. 3QQCh. 13.8 - Prob. 1QQCh. 13.8 - Prob. 2QQCh. 13.9 - Prob. 1QQCh. 13.9 - Prob. 2QQCh. 13.10 - Prob. 1QQCh. 13.10 - Prob. 2QQCh. 13.10 - Prob. 3QQCh. 13.10 - Prob. 4QQCh. 13.10 - Prob. 5QQCh. 13.11 - Prob. 1QQCh. 13.11 - Prob. 2QQCh. 13.11 - Prob. 3QQCh. 13.11 - Prob. 4QQCh. 13.11 - Prob. 5QQCh. 13.12 - Prob. 1QQCh. 13.12 - Prob. 2QQCh. 13.12 - Prob. 3QQCh. 13.12 - Prob. 4QQCh. 13.12 - Prob. 5QQCh. 13.13 - Prob. 1QQCh. 13.13 - Prob. 2QQCh. 13.13 - Prob. 3QQCh. 13.14 - Prob. 1QQCh. 13.14 - Prob. 2QQCh. 13.14 - Prob. 3QQCh. 13.14 - Prob. 4QQCh. 13.15 - Prob. 1QQCh. 13.15 - Prob. 2QQCh. 13.15 - Prob. 3QQCh. 13.15 - Prob. 4QQCh. 13.16 - Prob. 1QQCh. 13.16 - Prob. 2QQCh. 13 - Classify each of the following hydrocarbons as...Ch. 13 - Classify each of the following hydrocarbons as...Ch. 13 - Prob. 13.3EPCh. 13 - Prob. 13.4EPCh. 13 - Prob. 13.5EPCh. 13 - Prob. 13.6EPCh. 13 - Prob. 13.7EPCh. 13 - Prob. 13.8EPCh. 13 - Prob. 13.9EPCh. 13 - What is the molecular formula for each of the...Ch. 13 - Prob. 13.11EPCh. 13 - Prob. 13.12EPCh. 13 - What is wrong, if anything, with the following...Ch. 13 - Prob. 13.14EPCh. 13 - Prob. 13.15EPCh. 13 - Prob. 13.16EPCh. 13 - Prob. 13.17EPCh. 13 - Prob. 13.18EPCh. 13 - Draw a condensed structural formula for each of...Ch. 13 - Draw a condensed structural formula for each of...Ch. 13 - The following names are incorrect by IUPAC rules....Ch. 13 - The following names are incorrect by IUPAC rules....Ch. 13 - Prob. 13.23EPCh. 13 - Prob. 13.24EPCh. 13 - Prob. 13.25EPCh. 13 - Classify each of the following compounds as...Ch. 13 - Prob. 13.27EPCh. 13 - How many hydrogen atoms are present in a molecule...Ch. 13 - Prob. 13.29EPCh. 13 - Draw a line-angle structural formula for each of...Ch. 13 - Prob. 13.31EPCh. 13 - Prob. 13.32EPCh. 13 - Prob. 13.33EPCh. 13 - Prob. 13.34EPCh. 13 - Prob. 13.35EPCh. 13 - Prob. 13.36EPCh. 13 - Prob. 13.37EPCh. 13 - Prob. 13.38EPCh. 13 - For each of the following pairs of alkenes,...Ch. 13 - Prob. 13.40EPCh. 13 - Prob. 13.41EPCh. 13 - Prob. 13.42EPCh. 13 - Prob. 13.43EPCh. 13 - Prob. 13.44EPCh. 13 - Prob. 13.45EPCh. 13 - Prob. 13.46EPCh. 13 - For each molecule, indicate whether cistrans...Ch. 13 - For each molecule, indicate whether cistrans...Ch. 13 - Prob. 13.49EPCh. 13 - Prob. 13.50EPCh. 13 - Prob. 13.51EPCh. 13 - Draw a structural formula for each of the...Ch. 13 - Prob. 13.53EPCh. 13 - Prob. 13.54EPCh. 13 - Prob. 13.55EPCh. 13 - Prob. 13.56EPCh. 13 - Prob. 13.57EPCh. 13 - Prob. 13.58EPCh. 13 - Why is the number of carbon atoms in a terpene...Ch. 13 - How many isoprene units are present in a....Ch. 13 - Prob. 13.61EPCh. 13 - Indicate whether each of the following statements...Ch. 13 - Prob. 13.63EPCh. 13 - With the help of Figure 13-7, indicate whether...Ch. 13 - Prob. 13.65EPCh. 13 - Prob. 13.66EPCh. 13 - Prob. 13.67EPCh. 13 - Prob. 13.68EPCh. 13 - Prob. 13.69EPCh. 13 - Prob. 13.70EPCh. 13 - Prob. 13.71EPCh. 13 - Prob. 13.72EPCh. 13 - Prob. 13.73EPCh. 13 - Prob. 13.74EPCh. 13 - Prob. 13.75EPCh. 13 - Write a chemical equation showing reactants,...Ch. 13 - Supply the structural formula of the product in...Ch. 13 - Prob. 13.78EPCh. 13 - What reactant would you use to prepare each of the...Ch. 13 - Prob. 13.80EPCh. 13 - Prob. 13.81EPCh. 13 - Prob. 13.82EPCh. 13 - Prob. 13.83EPCh. 13 - Prob. 13.84EPCh. 13 - Prob. 13.85EPCh. 13 - Prob. 13.86EPCh. 13 - Prob. 13.87EPCh. 13 - Prob. 13.88EPCh. 13 - Prob. 13.89EPCh. 13 - Prob. 13.90EPCh. 13 - Prob. 13.91EPCh. 13 - Prob. 13.92EPCh. 13 - Prob. 13.93EPCh. 13 - What are the bond angles about the triple bond in...Ch. 13 - Prob. 13.95EPCh. 13 - Prob. 13.96EPCh. 13 - Prob. 13.97EPCh. 13 - Prob. 13.98EPCh. 13 - Prob. 13.99EPCh. 13 - Prob. 13.100EPCh. 13 - Prob. 13.101EPCh. 13 - Prob. 13.102EPCh. 13 - Prob. 13.103EPCh. 13 - Prob. 13.104EPCh. 13 - Prob. 13.105EPCh. 13 - Prob. 13.106EPCh. 13 - Prob. 13.107EPCh. 13 - Prob. 13.108EPCh. 13 - Assign each of the compounds in Problem 13-107 an...Ch. 13 - Assign each of the compounds in Problem 13-108 an...Ch. 13 - Prob. 13.111EPCh. 13 - Prob. 13.112EPCh. 13 - Prob. 13.113EPCh. 13 - Prob. 13.114EPCh. 13 - Prob. 13.115EPCh. 13 - Write a structural formula for each of the...Ch. 13 - Eight isomeric substituted benzenes have the...Ch. 13 - Prob. 13.118EPCh. 13 - Prob. 13.119EPCh. 13 - Prob. 13.120EPCh. 13 - Prob. 13.121EPCh. 13 - Prob. 13.122EPCh. 13 - Prob. 13.123EPCh. 13 - Prob. 13.124EPCh. 13 - Prob. 13.125EPCh. 13 - For each of the following classes of compounds,...Ch. 13 - Prob. 13.127EPCh. 13 - Prob. 13.128EPCh. 13 - Prob. 13.129EPCh. 13 - Prob. 13.130EP
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Text book image
World of Chemistry, 3rd edition
Chemistry
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Brooks / Cole / Cengage Learning
Text book image
World of Chemistry
Chemistry
ISBN:9780618562763
Author:Steven S. Zumdahl
Publisher:Houghton Mifflin College Div
Text book image
Introductory Chemistry For Today
Chemistry
ISBN:9781285644561
Author:Seager
Publisher:Cengage
Text book image
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning
Text book image
Introductory Chemistry: An Active Learning Approa...
Chemistry
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Cengage Learning
Text book image
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chapter 4 Alkanes and Cycloalkanes Lesson 2; Author: Linda Hanson;https://www.youtube.com/watch?v=AL_CM_Btef4;License: Standard YouTube License, CC-BY
Chapter 4 Alkanes and Cycloalkanes Lesson 1; Author: Linda Hanson;https://www.youtube.com/watch?v=PPIa6EHJMJw;License: Standard Youtube License