A uniform sphere with mass 50.0 kg is held with its center at the origin, and a second uniform sphere with mass 80.0 kg is held with its center at the point x = 0, y = 3.00 m. (a) What are the magnitude and direction of the net gravitational force due to these objects on a third uniform sphere with mass 0.500 kg placed at the point a x = 4.00 m, y = 0? (b) Where, other than infinitely far away, could the third sphere be placed such that the net gravitational force acting on it from the other two spheres is equal to zero?
A uniform sphere with mass 50.0 kg is held with its center at the origin, and a second uniform sphere with mass 80.0 kg is held with its center at the point x = 0, y = 3.00 m. (a) What are the magnitude and direction of the net gravitational force due to these objects on a third uniform sphere with mass 0.500 kg placed at the point a x = 4.00 m, y = 0? (b) Where, other than infinitely far away, could the third sphere be placed such that the net gravitational force acting on it from the other two spheres is equal to zero?
A uniform sphere with mass 50.0 kg is held with its center at the origin, and a second uniform sphere with mass 80.0 kg is held with its center at the point x = 0, y = 3.00 m. (a) What are the magnitude and direction of the net gravitational force due to these objects on a third uniform sphere with mass 0.500 kg placed at the point a x = 4.00 m, y = 0? (b) Where, other than infinitely far away, could the third sphere be placed such that the net gravitational force acting on it from the other two spheres is equal to zero?
I do not understand the process to answer the second part of question b. Please help me understand how to get there!
Rank the six combinations of electric charges on the basis of the electric force acting on 91. Define forces pointing to the right as positive and forces pointing to the left as negative.
Rank in increasing order by placing the most negative on the left and the most positive on the right. To rank items as equivalent, overlap them.
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[most negative
91 = +1nC
92 = +1nC
91 = -1nC
93 = +1nC
92- +1nC
93 = +1nC
-1nC
92- -1nC
93- -1nC
91= +1nC
92 = +1nC
93=-1nC
91
+1nC
92=-1nC
93=-1nC
91 = +1nC
2 = −1nC
93 = +1nC
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most positive
Part A
Find the x-component of the electric field at the origin, point O.
Express your answer in newtons per coulomb to three significant figures, keeping in mind that an x component that points to the right is positive.
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Eoz =
Η ΑΣΦ
?
N/C
Submit
Part B
Now, assume that charge q2 is negative; q2 = -6 nC, as shown in (Figure 2). What is the x-component of the net electric field at the origin, point O?
Express your answer in newtons per coulomb to three significant figures, keeping in mind that an x component that points to the right is positive.
▸ View Available Hint(s)
Eoz=
Η ΑΣΦ
?
N/C
Campbell Essential Biology with Physiology (5th Edition)
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