Concept explainers
(a)
Interpretation:
An
Concept introduction:
E2 stands for bimolecular elimination. This reaction is a one-step concerted mechanism. In this step, the C-X and C-H bond breaks to form a double bond. The leaving group and the adjacent hydrogen atom must be anticoplanar in the precursor for the E2 step to be favored. To arrive back at the alkyl halide, one must add hydrogen and a halogen on the alkene carbons in an anti-fashion.
Since the alkyl halide and base influence the
Answer to Problem 13.35P
An alkyl halide that could have been used to synthesize the known alkene exclusively via an E2 reaction paying attention to stereochemistry is:
Explanation of Solution
The structure of the desired alkene is:
The given alkene has both the higher priority groups attached on the opposite side of the double bond. Hence, the stereochemistry is E. Alkenes can be prepared from corresponding alkyl halides via E2 reactions. This reaction is a one-step concerted mechanism. In this step, the C-X and C-H bond breaks to form a double bond. The leaving group and the adjacent hydrogen atom must be anticoplanar in the precursor for the E2 step to be favored. To arrive back at the alkyl halide, one must add hydrogen and a halogen on the alkene carbons in an anti-fashion. Thus, the original alkyl halide that could have been used to prepare the given alkene must be:
To arrive back at the alkyl halide, one must add hydrogen and a halogen on the alkene carbons in an anti-fashion.
(b)
Interpretation:
An alkyl halide, that can be used to synthesize the given alkene exclusively via an E2 reaction paying attention to stereochemistry, is to be provided.
Concept introduction:
The name E2 represents bimolecular elimination. This reaction is a one-step concerted mechanism. In this step, the C-X and C-H bond breaks to form a double bond. The leaving group and the adjacent hydrogen atom must be anticoplanar in the precursor for the E2 step to be favored. To arrive back at the alkyl halide, one must add hydrogen and a halogen on the alkene carbons in an anti-fashion.
Since the alkyl halide and base influence the rate of reaction, this is a bimolecular reaction. A strong base is used to form the most substituted alkene as the major product.
Answer to Problem 13.35P
An alkyl halide that could have been used to prepare the given alkene exclusively via an E2 reaction paying attention to stereochemistry is:
Explanation of Solution
The structure of the required alkene is:
The given alkene has both the most priority groups attached on the same side of the double bond. Therefore, the stereochemistry about the double bond is Z. Alkenes can be prepared from corresponding alkyl halides via E2 reactions. This reaction is a one-step concerted mechanism. In this step, the C-X and C-H bond breaks to form a double bond. The leaving group and the adjacent hydrogen atom must be anticoplanar in the precursor for the E2 step to be favored. To arrive back at the alkyl halide, one must add hydrogen and a halogen on the alkene carbons in an anti-fashion. Thus, the original alkyl halide that could have been used to prepare the given alkene must be:
To arrive back at the alkyl halide, one must add hydrogen and a halogen on the alkene carbons in an anti-fashion.
(c)
Interpretation:
An alkyl halide, that can be used to synthesize the given alkene exclusively via an E2 reaction paying attention to stereochemistry, is to be provided.
Concept introduction:
The name E2 represents bimolecular elimination. This reaction is a one-step concerted mechanism. In this step, the C-X and C-H bond breaks to form a double bond. The leaving group and the adjacent hydrogen atom must be anticoplanar in the precursor for the E2 step to be favored. To arrive back at the alkyl halide, one must add hydrogen and a halogen on the alkene carbons in an anti-fashion.
Since the alkyl halide and base influence the rate of reaction, this is a bimolecular reaction. A strong base is used to form the most substituted alkene as the major product.
Answer to Problem 13.35P
An alkyl halide that could have been used to prepare the given alkene exclusively via an E2 reaction paying attention to stereochemistry is:
Explanation of Solution
The structure of the desired alkene is:
The alkene is a cycloalkene having two methyl groups attached to the double-bonded carbon atoms. As the carbon atoms in alkenes are
To arrive back at the alkyl halide, one must add hydrogen and a halogen on the alkene carbons in an anti-fashion.
(d)
Interpretation:
An alkyl halide, that can be used to synthesize the given alkene exclusively via an E2 reaction paying attention to stereochemistry, is to be provided.
Concept introduction:
The name E2 represents bimolecular elimination. This reaction is a one-step concerted mechanism. In this step, the C-X and C-H bond breaks to form a double bond. The leaving group and the adjacent hydrogen atom must be anticoplanar in the precursor for the E2 step to be favored. To arrive back at the alkyl halide, one must add hydrogen and a halogen on the alkene carbons in an anti-fashion.
Since the alkyl halide and base influence the rate of reaction, this is a bimolecular reaction. A strong base is used to form the most substituted alkene as the major product.
Answer to Problem 13.35P
An alkyl halide that could have been used to prepare the given alkene exclusively via an E2 reaction paying attention to stereochemistry is:
Explanation of Solution
The structure of the desired alkene is:
The alkene is cyclohexene having three methyl groups as substituents.
As the carbon atoms in alkenes are sp2 hybridized, all the atoms that are directly attached to the double-bonded carbon atoms must be in the plane. There are two chiral centers in the molecule at C3 and C6 carbon atoms. The stereochemistry for those two chiral centers will not change and will be retained as the reaction does not occur at those two chiral centers. Alkenes can be prepared from corresponding alkyl halides via E2 reactions.
This reaction is a one-step concerted mechanism. In this step, the C-X and C-H bond breaks to form a double bond. The leaving group and the adjacent hydrogen atom must be anticoplanar in the precursor for the E2 step to be favored. To arrive back at the alkyl halide, one must add hydrogen and a halogen on the alkene carbons in an anti-fashion. Thus, the original alkyl halide that could have been used to prepare the given alkene must be:
To arrive back at the alkyl halide, one must add hydrogen and a halogen on the alkene carbons in an anti-fashion.
(e)
Interpretation:
An alkyl halide, that can be used to synthesize the given alkene exclusively via an E2 reaction paying attention to stereochemistry, is to be provided.
Concept introduction:
The name E2 represents bimolecular elimination. This reaction is a one-step concerted mechanism. In this step, the C-X and C-H bond breaks to form a double bond. The leaving group and the adjacent hydrogen atom must be anticoplanar in the precursor for the E2 step to be favored. To arrive back at the alkyl halide, one must add hydrogen and a halogen on the alkene carbons in an anti-fashion.
Since the alkyl halide and base influence the rate of reaction, this is a bimolecular reaction. A strong base is used to form the most substituted alkene as the major product.
Answer to Problem 13.35P
An alkyl halide that could have been used to prepare the given alkene exclusively via an E2 reaction paying attention to stereochemistry is:
Explanation of Solution
The structure of the desired alkene is:
The alkene is cyclohexene having three methyl groups as substituents.
As the carbon atoms in alkenes are sp2 hybridized, all the atoms that are directly attached to the double-bonded carbon atoms must be in the plane. There are two chiral centers in the molecule at C3 and C6 carbon atoms. The stereochemistry for those two chiral centers will not change and will be retained as the reaction does not occur at those two chiral centers. Alkenes can be prepared from corresponding alkyl halides via E2 reactions.
This reaction involves a one-step mechanism (concerted) in which carbon-halogen bond and carbon-hydrogen bond breaks to form a double bond. The leaving group and the adjacent hydrogen atom must be anticoplanar in the precursor for the E2 step to be favored. To arrive back at the alkyl halide, one must add hydrogen and a halogen on the alkene carbons in an anti-fashion. Thus, the original alkyl halide that could have been used to synthesize the given alkene must be:
To arrive back at the alkyl halide, one must add hydrogen and a halogen on the alkene carbons in an anti-fashion.
Want to see more full solutions like this?
Chapter 13 Solutions
Organic Chemistry: Principles And Mechanisms: Study Guide/solutions Manual (second)
- Draw the complete, detailed E1 mechanism for each of the following reactions, and show all resonance structures, where applicable.arrow_forwardFor each of the following reactions draw the structure of the major organic product in the box provided.Each numbered set of reagents above or below the arrow represents a complete separate reaction.For multi-step reactions give only the structure of the final product.arrow_forwardDraw a mechanism to account for the formation of the NaOH product in the reaction shown here. Hint: Under these A conditions, deprotonation of a propargylic (C=C-CH) carbon is reversible.arrow_forward
- First, draw the structure of the alkyl bromide that will ONLY give the alkene shown in an elimination reaction; then, draw the structure of the alkyl bromide that will give a mixture of alkene products in an elimination reaction.arrow_forwardWhich reaction in each of the following pairs would you expect to be faster? (i) Write both reactions using bond-line presentation and, using arrows providing a mechanistic explanation of the course of the reaction, draw either a transition state or an intermediate product of the reaction; (ii) Shortly (one sentence) explain your reasoning why one of the two reactions will be faster.arrow_forward(SYN) 1,4-Cyclohexanedione monoethylene acetal is commercially available. (a) Show how you would use it to synthesize 4-ethylidenecyclohexanone. (b) What problems would arise if you tried to synthesize the same target from 1,4-cyclohexanedione? ? 1,4-Cyclohexanedione monoethylene acetal 4-Ethylidenecyclohexanonearrow_forward
- Will each of the following reactions follow an El or E2 mechanism? to to HO,arrow_forward(SYN) Propose how you would carry out the transformation shown here. Hint: It may take more than a single reaction. OH OH ? + Enantiomer Br ОНarrow_forwardI. Of the following reactions, answer what is requested:a) Analyze the type of alkyl halide and determine if the nucleophile is strong or weak and also if it has a basic character.b) According to the previous paragraph, determine if there is competition between the substitution and elimination reactions.c) Describe the mechanism of each of the product (s) that are formedd) Of the product (s) that are formed, indicate which one comes from the substitution reaction and which one from eliminatione) If two or more products are formed, indicate which would be the majority and explain why.arrow_forward
- For the following problem, supply all organic products. The only mechanism followed for each of the nucleophiles is substitution. You DO NOT need to write out a mechanism for this question, only supply products. NaSeCH3arrow_forwardA thiophene ring is sufficiently activated that bromination may take place without the presence of a Lewis acid catalyst. With this in mind, draw the complete mechanism for the reaction shown here and predict the majorproductarrow_forwardDraw a complete, step-wise, curved arrow mechanism for each reaction shown below. You don't need to worry about stereochemistry for these problems. It may help if you take the following steps. 1) Find the nucleophile and the electrophile. 2) Determine the major functional group present in the nucleophile and electrophile. 3) Determine the type of reaction this particular nucleophile/electrophile pair is likely to participate in 4) Draw the mechanism that corresponds with this reaction type. a) OH cat. H2SO4 HO Cl2 b) :OHarrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning