Chapter 13, Problem 13.15QP

(a)

Interpretation Introduction

Interpretation: The molality of solution that is $\text{14}\text{.3 g}$ Sucrose $\left({\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}\right)$ in $\text{676g}$ of water should be calculated.

Concept introduction

Molality$\left(m\right)$: The concentration for solutions is expressed in terms of molality. Molality is the number of moles of solute present in one kilogram of solvent. Molality is estimation of moles in relationship with solvent in the solution.

$\text{Molality (m) =}\frac{\text{Number}\text{of}\text{moles}\text{of}\text{solute}}{\text{kilograms}\text{of}\text{solvent}}$

(b)

Interpretation Introduction

Interpretation: The molality of solution that is $\text{7}\text{.20}$ moles of Ethylene glycol $\left({\text{C}}_{\text{2}}{\text{H}}_{\text{6}}{\text{O}}_{\text{2}}\right)$ in $\text{3546g}$ of water should be calculated.

Concept introduction

Molality$\left(m\right)$: The concentration for solutions is expressed in terms of molality. Molality is the number of moles of solute present in one kilogram of solvent. Molality is estimation of moles in relationship with solvent in the solution.

$\text{Molality (m) =}\frac{\text{Number}\text{of}\text{moles}\text{of}\text{solute}}{\text{kilograms}\text{of}\text{solvent}}$