Chapter 13, Problem 13.147QP

Interpretation Introduction

Interpretation: $\text{1}\text{.00ppm}$ ${\text{F}}^{\text{-}}$ to percent by mass to be converted and molality of $\text{NaF}$  has to be determined.

Concept introduction:

Molality: Molality is described as number of moles of the solute dissolved in one kilogram of the solvent. It will given by,

$\text{Molality =}\frac{\text{moles of the solute}}{\text{kg sovent}}$

Percent by mass: Mass percent is mass of the element is divided by total mass of the compound and multiplied by 100.

                $\text{Percent mass =}\frac{\text{Mass}\text{of}\text{the}\text{element}}{\text{total}\text{mass}\text{of}\text{the}\text{compound}}\text{×100\%}$