(a) Interpretation: The mole percent of the each given compound in the mixture is to be stated. Concept introduction: NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy. The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton lesser will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 1

Question

Chapter 13, Problem 13.12P

Interpretation Introduction

(a)

Interpretation:

The mole percent of the each given compound in the mixture is to be stated.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton lesser will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Interpretation Introduction

(b)

Interpretation:

Among 1 mole percent CH3I impurity in (CH3)3C−Br, and 1 mole percent (CH3)3C−Br impurity in CH3I, the one which is more easily detected by NMR is to be stated with an explanation.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton lesser will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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The functional groups in an organic compound can frequently be deduced from its infrared absorption spectrum. A compound containing no nitrogen exhibits strong, broad absorption across the 2500-3300 cm³¹ region, accompanied by 2200 (w) and 1715 (s) cm-¹ bands. Relative absorption intensity: (s)=strong, (m)=medium, (w)=weak. What functional class(es) does the compound belong to? List only classes for which evidence is given here. Attach no significance to evidence not cited explicitly. Do not over-interpret exact absorption band positions. None of your inferences should depend on small differences like 10 to 20 cm³¹. The functional class(es) of this compound is(are) . (Enter letters from the table below, in any order, with no spaces or commas.) a. alkane (List only if no other functional class applies.) b. alkene c. terminal alkyne d. internal alkyne e. arene f. alcohol g. ether h. amine i. aldehyde or ketone j.carboxylic acid k. ester I. nitrile

A common lab experiment is the dehydration of cyclohexanol to cyclohexene.(a) Explain how you could tell from the IR spectrum whether your product was pure cyclohexene, pure cyclohexanol,or a mixture of cyclohexene and cyclohexanol. Give approximate frequencies for distinctive peaks.

7a

Answer 2

Question

Chapter 13, Problem 13.12P

Interpretation Introduction

(a)

Interpretation:

The mole percent of the each given compound in the mixture is to be stated.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton lesser will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Interpretation Introduction

(b)

Interpretation:

Among 1 mole percent CH3I impurity in (CH3)3C−Br, and 1 mole percent (CH3)3C−Br impurity in CH3I, the one which is more easily detected by NMR is to be stated with an explanation.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton lesser will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 3

Question

Chapter 13, Problem 13.12P

Interpretation Introduction

(a)

Interpretation:

The mole percent of the each given compound in the mixture is to be stated.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton lesser will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Interpretation Introduction

(b)

Interpretation:

Among 1 mole percent CH3I impurity in (CH3)3C−Br, and 1 mole percent (CH3)3C−Br impurity in CH3I, the one which is more easily detected by NMR is to be stated with an explanation.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton lesser will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 4

Question

Chapter 13, Problem 13.12P

Interpretation Introduction

(a)

Interpretation:

The mole percent of the each given compound in the mixture is to be stated.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton lesser will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Interpretation Introduction

(b)

Interpretation:

Among 1 mole percent CH3I impurity in (CH3)3C−Br, and 1 mole percent (CH3)3C−Br impurity in CH3I, the one which is more easily detected by NMR is to be stated with an explanation.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton lesser will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 5

Chapter 13, Problem 13.12P

Interpretation Introduction

(a)

Interpretation:

The mole percent of the each given compound in the mixture is to be stated.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton lesser will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Interpretation Introduction

(b)

Interpretation:

Among 1 mole percent CH3I impurity in (CH3)3C−Br, and 1 mole percent (CH3)3C−Br impurity in CH3I, the one which is more easily detected by NMR is to be stated with an explanation.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton lesser will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 6

Chapter 13, Problem 13.12P

Interpretation Introduction

(a)

Interpretation:

The mole percent of the each given compound in the mixture is to be stated.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton lesser will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 7

Chapter 13, Problem 13.12P

Interpretation Introduction

(a)

Interpretation:

The mole percent of the each given compound in the mixture is to be stated.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton lesser will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 8

Interpretation Introduction

(b)

Interpretation:

Among 1 mole percent CH3I impurity in (CH3)3C−Br, and 1 mole percent (CH3)3C−Br impurity in CH3I, the one which is more easily detected by NMR is to be stated with an explanation.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton lesser will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 9

Interpretation Introduction

(b)

Interpretation:

Among 1 mole percent CH3I impurity in (CH3)3C−Br, and 1 mole percent (CH3)3C−Br impurity in CH3I, the one which is more easily detected by NMR is to be stated with an explanation.

Concept introduction:

NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy.

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton lesser will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 13 - Prob. 13.1P Ch. 13 - Prob. 13.2P Ch. 13 - Prob. 13.3P Ch. 13 - Prob. 13.4P Ch. 13 - Prob. 13.5P Ch. 13 - Prob. 13.6P Ch. 13 - Prob. 13.7P Ch. 13 - Prob. 13.8P Ch. 13 - Prob. 13.9P Ch. 13 - Prob. 13.10P

Solution Summary: The author explains that NMR spectroscopy identifies the carbon-hydrogen bonding of an organic compound.

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Chapter 13 Solutions