Organic Chemistry
Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Textbook Question
Book Icon
Chapter 12.SE, Problem 33AP

At what approximate positions might the following compounds show IR absorptions?

Chapter 12.SE, Problem 33AP, At what approximate positions might the following compounds show IR absorptions?

Expert Solution
Check Mark
Interpretation Introduction

a)

Interpretation:

The approximate absorption frequency has to be given for compound.

Concept introduction:

Spectroscopy: It is study of the interaction of matter and electromagnetic radiation, a continuum of different types of electromagnetic radiation each associated with a particular energy range makes up the electromagnetic spectrum.

IR frequency (cm-1): It is the number of wave crests that pass by a given point in one second frequency has units of hertz (Hz).

Stretch vibrations: It is a vibration occurring along the line of the bond a stretching vibration changes the bond length.

Bending vibrations: It is a vibration that does not occur along the line of the bond, bending vibration changes the bond angle.

Answer to Problem 33AP

The IR absorptions values at 1450-1600 cm-1 is for carbon double bond carbon stretching frequency, 3030 cm-1 is for aromatic carbon hydrogen stretching frequency, 1710-1760 cm-1 is for acid carbonyl frequency and 2500-3100 cm-1 is for acid hydroxyl frequency.

Explanation of Solution

Given information:

The approximate absorption frequency for the given compound,

Organic Chemistry, Chapter 12.SE, Problem 33AP , additional homework tip  1

The IR absorptions values at 1450-1600 cm-1 is for carbon double bond carbon stretching frequency, 3030 cm-1 is for aromatic carbon hydrogen stretching frequency, 1710-1760 cm-1 is for acid carbonyl frequency and 2500-3100 cm-1 is for acid hydroxyl frequency.

Therefore, the approximate absorption frequency for the given compound is shown below,

Organic Chemistry, Chapter 12.SE, Problem 33AP , additional homework tip  2

Conclusion

The approximate absorption frequency is given for compound.

Expert Solution
Check Mark
Interpretation Introduction

b)

Interpretation:

The approximate absorption frequency has to be given for compound.

Concept introduction:

Spectroscopy: It is study of the interaction of matter and electromagnetic radiation, a continuum of different types of electromagnetic radiation each associated with a particular energy range makes up the electromagnetic spectrum.

IR frequency (cm-1): It is the number of wave crests that pass by a given point in one second frequency has units of hertz (Hz).

Stretch vibrations: It is a vibration occurring along the line of the bond a stretching vibration changes the bond length.

Bending vibrations: It is a vibration that does not occur along the line of the bond, bending vibration changes the bond angle.

Answer to Problem 33AP

The IR absorptions values at 1450-1600 cm-1 is for carbon double bond carbon stretching frequency, 3030 cm-1 is for aromatic carbon hydrogen stretching frequency, 1710-1760 cm-1 is for acid carbonyl frequency and 2500-3100 cm-1 is for acid hydroxyl frequency.

Explanation of Solution

Given information:

The approximate absorption frequency for the given compound,

Organic Chemistry, Chapter 12.SE, Problem 33AP , additional homework tip  3

The IR absorptions values at 1450-1600 cm-1 is for carbon double bond carbon stretching frequency, 3030 cm-1 is for aromatic carbon hydrogen stretching frequency, 1710-1760 cm-1 is for acid carbonyl frequency and 2500-3100 cm-1 is for acid hydroxyl frequency.

Therefore, the approximate absorption frequency for the given compound is shown below,

Organic Chemistry, Chapter 12.SE, Problem 33AP , additional homework tip  4

Conclusion

The difference between given pairs of isomers is explained by using infrared spectroscopy.

Expert Solution
Check Mark
Interpretation Introduction

c)

Interpretation:

The difference between given pairs of isomer has to be explained by using infrared spectroscopy.

Concept introduction:

Spectroscopy: It is study of the interaction of matter and electromagnetic radiation, a continuum of different types of electromagnetic radiation each associated with a particular energy range makes up the electromagnetic spectrum.

IR frequency (cm-1): It is the number of wave crests that pass by a given point in one second frequency has units of hertz (Hz).

Stretch vibrations: It is a vibration occurring along the line of the bond a stretching vibration changes the bond length.

Bending vibrations: It is a vibration that does not occur along the line of the bond, bending vibration changes the bond angle.

Answer to Problem 33AP

The IR absorptions values at 1450-1600 cm-1 is for carbon double bond carbon stretching frequency, 3030 cm-1 is for aromatic carbon hydrogen stretching frequency, 2210-2260 cm-1 is for acid carbonyl frequency and 3400-3650 cm-1 is for acid hydroxyl frequency.

Explanation of Solution

Given information:

The approximate absorption frequency for the given compound,

Organic Chemistry, Chapter 12.SE, Problem 33AP , additional homework tip  5

The IR absorptions values at 1450-1600 cm-1 is for carbon double bond carbon stretching frequency, 3030 cm-1 is for aromatic carbon hydrogen stretching frequency, 2210-2260 cm-1 is for acid carbonyl frequency and 3400-3650 cm-1 is for acid hydroxyl frequency.

Therefore, the approximate absorption frequency for the given compound is shown below,

Organic Chemistry, Chapter 12.SE, Problem 33AP , additional homework tip  6

Conclusion

The difference between given pairs of isomers is explained by using infrared spectroscopy.

Expert Solution
Check Mark
Interpretation Introduction

d)

Interpretation:

The difference between given pairs of isomer has to be explained by using infrared spectroscopy.

Concept introduction:

Spectroscopy: It is study of the interaction of matter and electromagnetic radiation, a continuum of different types of electromagnetic radiation each associated with a particular energy range makes up the electromagnetic spectrum.

IR frequency (cm-1): It is the number of wave crests that pass by a given point in one second frequency has units of hertz (Hz).

Stretch vibrations: It is a vibration occurring along the line of the bond a stretching vibration changes the bond length.

Bending vibrations: It is a vibration that does not occur along the line of the bond, bending vibration changes the bond angle.

Answer to Problem 33AP

The IR absorptions values at 1640-1680 cm-1 is for carbon double bond carbon stretching frequency, 3020-3100 cm-1 is for vinylic carbon hydrogen stretching frequency and 1715 cm-1 is for acid hydroxyl frequency.

Explanation of Solution

Given information:

The approximate absorption frequency for the given compound,

Organic Chemistry, Chapter 12.SE, Problem 33AP , additional homework tip  7

The IR absorptions values at 1640-1680 cm-1 is for carbon double bond carbon stretching frequency, 3020-3100 cm-1 is for vinylic carbon hydrogen stretching frequency and 1715 cm-1 is for acid hydroxyl frequency.

Therefore, the approximate absorption frequency for the given compound is shown below,

Organic Chemistry, Chapter 12.SE, Problem 33AP , additional homework tip  8

Conclusion

The difference between given pairs of isomers is explained by using infrared spectroscopy.

Expert Solution
Check Mark
Interpretation Introduction

e)

Interpretation:

The difference between given pairs of isomer has to be explained by using infrared spectroscopy.

Concept introduction:

Spectroscopy: It is study of the interaction of matter and electromagnetic radiation, a continuum of different types of electromagnetic radiation each associated with a particular energy range makes up the electromagnetic spectrum.

IR frequency (cm-1): It is the number of wave crests that pass by a given point in one second frequency has units of hertz (Hz).

Stretch vibrations: It is a vibration occurring along the line of the bond a stretching vibration changes the bond length.

Bending vibrations: It is a vibration that does not occur along the line of the bond, bending vibration changes the bond angle.

Answer to Problem 33AP

The IR absorptions values at 1715 cm-1 is for carbonyl (ketone) stretching frequency and 1735 cm-1 is for carbonyl ester frequency.

Explanation of Solution

Given information:

The approximate absorption frequency for the given compound,

Organic Chemistry, Chapter 12.SE, Problem 33AP , additional homework tip  9

The IR absorptions values at 1715 cm-1 is for carbonyl (ketone) stretching frequency and 1735 cm-1 is for carbonyl ester frequency.

Therefore, the approximate absorption frequency for the given compound is shown below,

Organic Chemistry, Chapter 12.SE, Problem 33AP , additional homework tip  10

Conclusion

The difference between given pairs of isomers is explained by using infrared spectroscopy.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Do the Lone Pairs get added bc its valence e's are a total of 6 for oxygen and that completes it or due to other reasons. How do we know the particular indication of such.
NGLISH b) Identify the bonds present in the molecule drawn (s) above. (break) State the function of the following equipments found in laboratory. Omka) a) Gas mask b) Fire extinguisher c) Safety glasses 4. 60cm³ of oxygen gas diffused through a porous hole in 50 seconds. How long w 80cm³ of sulphur(IV) oxide to diffuse through the same hole under the same conditions (S-32.0.0-16.0) (3 m 5. In an experiment, a piece of magnesium ribbon was cleaned with steel w clean magnesium ribbon was placed in a crucible and completely burnt in oxy cooling the product weighed 4.0g a) Explain why it is necessary to clean magnesium ribbon. Masterclass Holiday assignmen PB 2
Hi!! Please provide a solution that is handwritten. Ensure all figures, reaction mechanisms (with arrows and lone pairs please!!), and structures are clearly drawn to illustrate the synthesis of the product as per the standards of a third year organic chemistry course. ****the solution must include all steps, mechanisms, and intermediate structures as required. Please hand-draw the mechanisms and structures to support your explanation. Don’t give me AI-generated diagrams or text-based explanations, no wordy explanations on how to draw the structures I need help with the exact mechanism hand drawn by you!!!    I am reposting this—ensure all parts of the question are straightforward and clear or please let another expert handle it thanks!!

Chapter 12 Solutions

Organic Chemistry

Ch. 12.8 - Where might the following compound have IR...Ch. 12.SE - Prob. 12VCCh. 12.SE - Show the structures of the fragments you would...Ch. 12.SE - Propose structures for compounds that fit the...Ch. 12.SE - Write molecular formulas for compounds that show...Ch. 12.SE - Camphor, a saturated monoketone from the Asian...Ch. 12.SE - The nitrogen rule of mass spectrometry says that a...Ch. 12.SE - In light of the nitrogen rule mentioned in Problem...Ch. 12.SE - Nicotine is a diamino compound isolated from dried...Ch. 12.SE - The hormone cortisone contains C, H, and O, and...Ch. 12.SE - Halogenated compounds are particularly easy to...Ch. 12.SE - Prob. 22APCh. 12.SE - Propose structures for compounds that fit the...Ch. 12.SE - 2-Methylpentane (C6H14) has the mass spectrum...Ch. 12.SE - Assume that you are in a laboratory carrying out...Ch. 12.SE - What fragments might you expect in the mass...Ch. 12.SE - How might you use IR spectroscopy to distinguish...Ch. 12.SE - Would you expect two enantiomers such as...Ch. 12.SE - Would you expect two diastereomers such as meso-2,...Ch. 12.SE - Propose structures for compounds that meet the...Ch. 12.SE - How could you use infrared spectroscopy to...Ch. 12.SE - Prob. 32APCh. 12.SE - At what approximate positions might the following...Ch. 12.SE - How would you use infrared spectroscopy to...Ch. 12.SE - At what approximate positions might the following...Ch. 12.SE - Assume that you are carrying out the dehydration...Ch. 12.SE - Assume that you are carrying out the base-induced...Ch. 12.SE - Prob. 38APCh. 12.SE - Carvone is an unsaturated ketone responsible for...Ch. 12.SE - Prob. 40APCh. 12.SE - The mass spectrum (a) and the infrared spectrum...Ch. 12.SE - The mass spectrum (a) and the infrared spectrum...Ch. 12.SE - Propose structures for compounds that meet the...Ch. 12.SE - 4-Methyl-2-pentanone and 3-methylpentanal are...Ch. 12.SE - Grignard reagents undergo a general and very...Ch. 12.SE - Ketones undergo a reduction when treated with...Ch. 12.SE - Nitriles, R–=C≡N, undergo a hydrolysis...Ch. 12.SE - The infrared spectrum of the compound with the...Ch. 12.SE - The infrared spectrum of the compound with the...Ch. 12.SE - Prob. 50AP
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
  • Text book image
    Organic Chemistry
    Chemistry
    ISBN:9781305080485
    Author:John E. McMurry
    Publisher:Cengage Learning
    Text book image
    Organic Chemistry: A Guided Inquiry
    Chemistry
    ISBN:9780618974122
    Author:Andrei Straumanis
    Publisher:Cengage Learning
    Text book image
    Organic Chemistry
    Chemistry
    ISBN:9781305580350
    Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
    Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305080485
Author:John E. McMurry
Publisher:Cengage Learning
Text book image
Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
IR Spectroscopy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=_TmevMf-Zgs;License: Standard YouTube License, CC-BY