Chapter 12.6, Problem 56SPR

To determine

Calculate the total volume of the storage.

Answer to Problem 56SPR

The volume of the storage is $18,555,031f{t}^3$ .

Explanation of Solution

Given:

It is given in the question that there will be $24$ concrete cylindrical cells in which twenty of the cells are used for oil storage and the diameter is $75$ ft and the height is $210$ ft.

Concept Used:

In this, use the concept of volume of the cylinder i.e. $V=\pi r^{2}h$ .

Calculation: Here, $r=d÷2=75÷2=37.5$ , $h=210$

Now, volume of the cylinder

  $\begin{array}{l}V=\pi r^{2}h\\ $ V=\pi {(37.5)}^2(210)$V=\pi (295312.5)\\ V=927,281.25f{t}^3\end{array}$

The total storage for

  $20$ cells will be:

  $927,281.25f{t}^3\times 20=18,555,031f{t}^3$

Conclusion:

The volume is $18,555,031f{t}^3$ .