Chapter 12.6, Problem 11PE

Interpretation Introduction

Interpretation:

For given $202mL$ benzene solution consists $2.47g$ of organic polymer with osmotic pressure $\text{8}\text{.63}\text{mmHg}\text{at}{\text{21}}^{\text{o}}\text{C}$, the molar mass of organic polymer should be calculated.

Concept introduction

Osmotic pressure is the pressure that is needed to stop osmosis. Osmotic pressure of the solution is directly proportional to the concentration of the solution. We can calculate osmotic pressure by using this formula is given by,

Osmotic pressure $\text{(π) = MRT}$

Where,

$\text{M-}$ Molarity of the solution $\left(\text{mol/L}\right)$

$\text{R-}$ Ideal gas constant ($0.08206{\text{L atm mol}}^{\text{-1}}{\text{K}}^{\text{-1}}$)

$\text{T-}$ Temperature in Kelvin

Molarity (M): The concentration for solutions is expressed in terms of molarity. Molarity is number of moles of the solute present in liter of the solution.

$\text{Molarity = }\frac{\text{No}\text{. of moles of solute}}{\text{Volume of solution in L}}$

Moles: One mole is equivalent to the mass of the substance consists same number of units equal to the atoms present in $\text{12}\text{g}$ of ${}^{\text{12}}\text{C}$.

From given mass of substance moles could be calculated by using the following formula,

$\text{Moles}\text{of}\text{substance }\text{= }\frac{\text{Given}\text{mass}\text{of}\text{substance}}{\text{Molecular}\text{mass}}$