Percent ionisation of 0 .10M monoprotic acid HA has to be determined. Concept introduction: Osmotic pressure is the pressure that is needed to stop osmosis. Osmotic pressure of the solution is directly proportional to the concentration of the solution. We can calculate osmotic pressure by using this formula is given by, Osmotic pressure (π) = MRT Where, M- Molarity of the solution ( mol/L ) R- Ideal gas constant ( 0.08206 L atm mol -1 K -1 ) T- Temperature in Kelvin Percent by mass: It is the ratio of solute mass to the solution mass which finally multiplied by 100 . The formula for percent by mass calculation is as follows, Percent mass = Mass of solute Mass of solution ×100% Mass of solution = Mass of solute + Mass of solvent
Percent ionisation of 0 .10M monoprotic acid HA has to be determined. Concept introduction: Osmotic pressure is the pressure that is needed to stop osmosis. Osmotic pressure of the solution is directly proportional to the concentration of the solution. We can calculate osmotic pressure by using this formula is given by, Osmotic pressure (π) = MRT Where, M- Molarity of the solution ( mol/L ) R- Ideal gas constant ( 0.08206 L atm mol -1 K -1 ) T- Temperature in Kelvin Percent by mass: It is the ratio of solute mass to the solution mass which finally multiplied by 100 . The formula for percent by mass calculation is as follows, Percent mass = Mass of solute Mass of solution ×100% Mass of solution = Mass of solute + Mass of solvent
Solution Summary: The author explains that osmotic pressure is directly proportional to the concentration of the solution. Percent ionization of monoprotic acid is equal to 32%.
Percent ionisation of 0.10M monoprotic acid HA has to be determined.
Concept introduction:
Osmotic pressure is the pressure that is needed to stop osmosis. Osmotic pressure of the solution is directly proportional to the concentration of the solution. We can calculate osmotic pressure by using this formula is given by,
Osmotic pressure (π) = MRT
Where,
M- Molarity of the solution (mol/L)
R- Ideal gas constant (0.08206L atm mol-1K-1)
T- Temperature in Kelvin
Percent by mass: It is the ratio of solute mass to the solution mass which finally multiplied by 100. The formula for percent by mass calculation is as follows,
Percent mass =MassofsoluteMass of solution×100%Mass of solution = Mass of solute + Mass of solvent
Feedback (4/10)
30%
Retry
Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow
the arrows to draw the reactant and missing intermediates involved in this reaction.
Include all lone pairs and charges as appropriate. Ignore inorganic byproducts.
Incorrect, 6 attempts remaining
:0:
Draw the Reactant
H
H3CO
H-
HIO:
Ö-CH3
CH3OH2*
protonation
H.
a
H
(+)
H
Ο
CH3OH2
O:
H3C
protonation
CH3OH
deprotonation
>
CH3OH
nucleophilic addition
H.
HO
0:0
Draw Intermediate
a
X
Can I please get the blank spaces answered/answers?
1. Identify the following alkenes as E or Z
NH₂
Br
2. Draw the structures based on the IUPAC names
(3R,4R)-3-bromo-4-fluoro-
1-hexene
(Z)-4-bromo-2-iodo-3-ethyl-
3-heptene
تر
3. For the following, predict all possible elimination product(s) and circle the major product.
HO
H₂SO4
Heat
80
F4
OH
H2SO4
Heat
어요
F5
F6
1
A
DII
4
F7
F8
F9
%
&
5
6
7
* ∞
8
BAB
3
E
R
T
Y
U
9
F
D
G
H
J
K
O
A
F11
F10