Chapter 12.5, Problem 6PPC

Interpretation Introduction

Interpretation:

By adding $753\text{ J}$ heat to the sample on the left side, the temperature increase by $41.2°C.$ The temperature increase of the sample on the right side has to be calculated if same amount of energy is added to the sample on the right side.

Concept Introduction:

Specific heat of a substance refers to the quantity of heat per unit mass of substance that rises the temperature of the substance by one degree Celsius. The quantity of heat added and the specific heat is related as follows –

$\begin{array}{l}\text{q = m}\times \text{s}\times \Delta \text{T}\\ \text{where q = heat added}\\ \text{ m = mass of the substance}\\ \text{ s = specific heat of the substance}\\ \Delta \text{T = change in Temperature}\\ \end{array}$