
Interpretation
Iodine will more soluble in water or in carbon disulfide should be identified.
Concept Introduction
Like dissolves like principle: ‘Like dissolves like’ principle says that polar compounds including ionic compound should be more soluble in polar solvent. Likewise, non–polar compound should be more soluble in non–polar solvent. Other hand, compounds with similar intermolecular force (hydrogen bonding is the principal intermolecular force) capability to soluble in one another because solute-solvent interactions are similar signification to the solute-solute interaction.
Note: Polar solvent should be having O atoms and N atoms with lone pairs.
Example, Methanol and water both are polar molecules. Methanol dissolves in water but Hexane does not dissolved in water because Hexane is non polar.
Polar molecule: Polar molecules have large dipole moments.
Non-Polar molecules: Non-polar molecules have bonded atoms with similar electronegativity results to have zero dipole moments.

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Chapter 12 Solutions
CHEMISTRY (LOOSELEAF) >CUSTOM<
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- LIOT S How would you make 200. mL of a 0.5 M solution of CuSO4 5H2O from solid copper (II) sulfate? View Rubricarrow_forwardSteps and explantions pleasearrow_forwardMatch the denticity to the ligand. Water monodentate ✓ C₂O2 bidentate H₂NCH₂NHCH2NH2 bidentate x EDTA hexadentate Question 12 Partially correct Mark 2 out of 2 Flag question Provide the required information for the coordination compound shown below: Na NC-Ag-CN] Number of ligands: 20 Coordination number: 2✔ Geometry: linear Oxidation state of transition metal ion: +3 x in 12 correct out of 2 question Provide the required information for the coordination compound shown below. Na NC-Ag-CN] Number of ligands: 20 Coordination number: 2 Geometry: linear 0 Oxidation state of transition metal ion: +3Xarrow_forward
- Can you explain step by step behind what the synthetic strategy would be?arrow_forwardPlease explain step by step in detail the reasoning behind this problem/approach/and answer. thank you!arrow_forward2. Predict the product(s) that forms and explain why it forms. Assume that any necessary catalytic acid is present. .OH HO H₂N OHarrow_forward
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