Concept explainers
Interpretation:
The general physical property of
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkanes are linear chain saturated hydrocarbons and cycloalkanes are cyclic carbon chain saturated hydrocarbons. They both occur naturally.
Alkanes and cycloalkanes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkanes and cycloalkanes do not get solubilized in water. In other words, alkanes and cycloalkanes are insoluble in water.
Regarding density, alkanes and cycloalkanes have density lower than water. When alkanes and cycloalkanes are mixed with water, two layers are formed which is a result of insolubility. Alkanes and cycloalkanes are present on top of water layer which is due to lesser density.
Boiling point of alkanes and cycloalkanes increase with an increase in carbon‑chain length or the ring size. When considering the continuous‑chain alkanes, the boiling point of alkanes increases about
When branching happens in the carbon chain, it lowers the boiling point of alkanes. In simple words, unbranched alkanes have more boiling point than branched alkanes with the same number of carbon atoms.
Cycloalkanes have more boiling point compared to noncyclic alkanes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropane and cyclobutane are gases at room temperature. Cyclopentane to cyclooctane are liquids at room temperature.
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Chapter 12 Solutions
Study Guide with Selected Solutions for Stoker's General, Organic, and Biological Chemistry, 7th
- Nonearrow_forward3. You may want to read paragraph 1.5 in your textbook before answering this question. Give electron configuration (short-hand notation is fine) for: (5 points) 3+ a) Manganese atom and Mn³+ b) Se atom c) Cu atom and Cu+arrow_forwardPlease correct answer and don't use hand ratingarrow_forward
- What is the preparation of 1 Liter of 0.1M NH4Cl buffer at pH 9.0 with solid NH4Cl and 0.1M NaOH. How would I calculate the math to describe this preparation? How would I use Henderson-Hasselbach equation?arrow_forwardC Predict the major products of this organic reaction. Be sure you use wedge and dash bonds when necessary, for example to distinguish between major products with different stereochemistry. : ☐ + x G C RCO₂H Click and drag to start drawing a structure.arrow_forwardFill in the blanks by selecting the appropriate term from below: For a process that is non-spontaneous and that favors products at equilibrium, we know that a) ΔrG∘ΔrG∘ _________, b) ΔunivSΔunivS _________, c) ΔsysSΔsysS _________, and d) ΔrH∘ΔrH∘ _________.arrow_forward
- Highest occupied molecular orbital Lowest unoccupied molecular orbital Label all nodes and regions of highest and lowest electron density for both orbitals.arrow_forwardRelative Intensity Part VI. consider the multi-step reaction below for compounds A, B, and C. These compounds were subjected to mass spectrometric analysis and the following spectra for A, B, and C was obtained. Draw the structure of B and C and match all three compounds to the correct spectra. Relative Intensity Relative Intensity 20 NaоH 0103 Br (B) H2504 → (c) (A) 100- MS-NU-0547 80 40 20 31 10 20 100- MS2016-05353CM 80 60 100 MS-NJ-09-3 80 60 40 20 45 J.L 80 S1 84 M+ absent राग 135 137 S2 62 164 166 11 S3 25 50 75 100 125 150 175 m/zarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning