
Concept explainers
(a)
Interpretation:
The unsubstituted cycloalkane that contains six carbon atoms will be solid, liquid, or gas at room temperature has to be given.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkanes and cycloalkanes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkanes and cycloalkanes do not get solubilized in water. In other words, alkanes and cycloalkanes are insoluble in water.
Regarding density, alkanes and cycloalkanes have density lower than water. When alkanes and cycloalkanes are mixed with water, two layers are formed which is a result of insolubility. Alkanes and cycloalkanes are present on top of water layer which is due to lesser density.
Boiling point of alkanes and cycloalkanes increase with an increase in carbon‑chain length or the ring size. When considering the continuous‑chain alkanes, the boiling point of alkanes increases about
When branching happens in the carbon chain, it lowers the boiling point of alkanes. In simple words, unbranched alkanes have more boiling point than branched alkanes with the same number of carbon atoms.
Cycloalkanes have higher boiling point compared to noncyclic alkanes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropane and cyclobutane are gases at room temperature. Cyclopentane to cyclooctane are liquids at room temperature.
(b)
Interpretation:
The unsubstituted cycloalkane that contains six carbon atoms is more or less dense than water has to be given.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkanes are linear chain saturated hydrocarbons and cycloalkanes are cyclic carbon chain saturated hydrocarbons. They both occur naturally.
Alkanes and cycloalkanes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkanes and cycloalkanes do not get solubilized in water. In other words, alkanes and cycloalkanes are insoluble in water.
Regarding density, alkanes and cycloalkanes have density lower than water. When alkanes and cycloalkanes are mixed with water, two layers are formed which is a result of insolubility. Alkanes and cycloalkanes are present on top of water layer which is due to lesser density.
Boiling point of alkanes and cycloalkanes increase with an increase in carbon‑chain length or the ring size. When considering the continuous‑chain alkanes, the boiling point of alkanes increases about
When branching happens in the carbon chain, it lowers the boiling point of alkanes. In simple words, unbranched alkanes have more boiling point than branched alkanes with the same number of carbon atoms.
Cycloalkanes have higher boiling point compared to noncyclic alkanes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropane and cyclobutane are gases at room temperature. Cyclopentane to cyclooctane are liquids at room temperature.
(c)
Interpretation:
The unsubstituted cycloalkane that contains six carbon atoms soluble or insoluble in water has to be given.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkanes are linear chain saturated hydrocarbons and cycloalkanes are cyclic carbon chain saturated hydrocarbons. They both occur naturally.
Alkanes and cycloalkanes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkanes and cycloalkanes do not get solubilized in water. In other words, alkanes and cycloalkanes are insoluble in water.
Regarding density, alkanes and cycloalkanes have density lower than water. When alkanes and cycloalkanes are mixed with water, two layers are formed which is a result of insolubility. Alkanes and cycloalkanes are present on top of water layer which is due to lesser density.
Boiling point of alkanes and cycloalkanes increase with an increase in carbon‑chain length or the ring size. When considering the continuous‑chain alkanes, the boiling point of alkanes increases about
When branching happens in the carbon chain, it lowers the boiling point of alkanes. In simple words, unbranched alkanes have more boiling point than branched alkanes with the same number of carbon atoms.
Cycloalkanes have higher boiling point compared to noncyclic alkanes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropane and cyclobutane are gases at room temperature. Cyclopentane to cyclooctane are liquids at room temperature.
(d)
Interpretation:
The unsubstituted cycloalkane that contains six carbon atoms will be flammable or inflammable has to be given.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkanes are linear chain saturated hydrocarbons and cycloalkanes are cyclic carbon chain saturated hydrocarbons. They both occur naturally.
Alkanes and cycloalkanes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkanes and cycloalkanes do not get solubilized in water. In other words, alkanes and cycloalkanes are insoluble in water.
Regarding density, alkanes and cycloalkanes have density lower than water. When alkanes and cycloalkanes are mixed with water, two layers are formed which is a result of insolubility. Alkanes and cycloalkanes are present on top of water layer which is due to lesser density.
Boiling point of alkanes and cycloalkanes increase with an increase in carbon‑chain length or the ring size. When considering the continuous‑chain alkanes, the boiling point of alkanes increases about
When branching happens in the carbon chain, it lowers the boiling point of alkanes. In simple words, unbranched alkanes have more boiling point than branched alkanes with the same number of carbon atoms.
Cycloalkanes have higher boiling point compared to noncyclic alkanes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropane and cyclobutane are gases at room temperature. Cyclopentane to cyclooctane are liquids at room temperature.

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Chapter 12 Solutions
Study Guide with Selected Solutions for Stoker's General, Organic, and Biological Chemistry, 7th
- What is the reaction mechanism for this?arrow_forwardPredict the major products of both organic reactions. Be sure to use wedge and dash bonds to show the stereochemistry of the products when it's important, for example to distinguish between two different major products. esc esc Explanation Check 2 : + + X H₁₂O + Х ง WW E R Y qab Ccaps lock shift $ P X Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility Bil T FR F18 9 G t K L Z X V B N M control opption command command T C darrow_forwardDraw the Markovnikov product of the hydrohalogenation of this alkene. this problem. Note for advanced students: draw only one product, and don't worry about showing any stereochemistry. Drawing dash and wedge bonds has been disabled for caps lock Explanation Check 2 W E R + X 5 HCI Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility Bil Y F G H K L ZZ X C V B N M control opption command F10 F10 command 4 BA Ar Carrow_forward
- I don't understand why the amide on the top left, with the R attached to one side, doesn't get substituted with OH to form a carboxylic acid. And if only one can be substituted, why did it choose the amide it chose rather than the other amide?arrow_forwardesc Draw the Markovnikov product of the hydration of this alkene. Note for advanced students: draw only one product, and don't worry about showing any stereochemistry. Drawing dash and wedge bonds has been disabled for this problem. Explanation Check BBB + X 0 1. Hg (OAc)2, H₂O 2. Na BH 5 Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility Bl P 豆 28 2 28 N 9 W E R T Y A S aps lock G H K L Z X C V B N M T central H command #e commandarrow_forwardC A student proposes the transformation below in one step of an organic synthesis. There may be one or more products missing from the right-hand side, but there are no reagents missing from the left-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing from the arrow. • Is the student's transformation possible? If not, check the box under the drawing area. . If the student's transformation is possible, then complete the reaction by adding any missing products to the right-hand side, and adding required catalysts, inorganic reagents, or other important reaction conditions above and below the arrow. • You do not need to balance the reaction, but be sure every important organic reactant or product is shown. (X) This transformation can't be done in one step. + Tarrow_forward
- く Predict the major products of this organic reaction. If there aren't any products, because nothing will happen, check the box under the drawing area instead. No reaction. Explanation Check OH + + ✓ 2 H₂SO 4 O xs H₂O 2 Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Centerarrow_forwardDraw the skeletal ("line") structure of 1,3-dihydroxy-2-pentanone. Click and drag to start drawing a structure. X Parrow_forwardPredicting edict the major products of this organic reaction. If there aren't any products, because nothing will happen, check the box under the drawing area instead. + No reaction. Explanation Check HO Na O H xs H₂O 2 Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Iarrow_forward
- Choosing reagents and conditions for acetal formation or hydrolysis 0/5 A student proposes the transformation below in one step of an organic synthesis. There may be one or more products missing from the right-hand side, but there are no reagents missing from the left-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing from the arrow. • Is the student's transformation possible? If not, check the box under the drawing area. If the student's transformation is possible, then complete the reaction by adding any missing products to the right-hand side, and adding required catalysts, inorganic reagents, or other important reaction conditions above and below the arrow. • You do not need to balance the reaction, but be sure every important organic reactant or product is shown. + This transformation can't be done in one step. 5 I H Autumn alo 值 Ar Barrow_forwardA block of copper of mass 2.00kg(cp = 0.3851 .K) and g temperature 0°C is introduced into an insulated container in which there is 1.00molH, O(g) at 100°C and 1.00 2 atm. Note that C P = 4.184. K for liquid water, and g that A H = 2260 for water. vap g Assuming all the steam is condensed to water, and that the pressure remains constant: (a) What will be the final temperature of the system? (b) What is the heat transferred from the water to the copper? (c) What is the entropy change of the water, the copper, and the total system?arrow_forwardIdentify the missing organic reactants in the following reaction: H+ X + Y OH H+ O O Note: This chemical equation only focuses on the important organic molecules in the reaction. Additional inorganic or small-molecule reactants or products (like H₂O) are not shown. In the drawing area below, draw the skeletal ("line") structures of the missing organic reactants X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Explanation Check Click and drag to start drawing a structure. X G 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Cente ? Earrow_forward
- Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
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