The earth’s rotation axis, which is tilted 23 . 5 ° from the plane of the earth’s orbit, today points to Polaris, the north star. But Polaris has not always been the north star because the earth, like a spinning gyroscope, precesses. That is, a line extending along the earth’s rotation axis traces out a 23.50 cone as the earth precesses with a period of 26,000 years. This occurs because the earth is not a perfect sphere. It has an equatorial bulge , which allows both the moon and the sun to exert a gravitational torque on the earth. Our expression for the precession frequency of a gyroscope can be written Ω = τ / I ω . Although we derived this equation for a specific situation, it’s a valid result, differing by at most a constant close to 1, for the precession of any rotating object. What is the average gravitational torque on the earth due to the moon and the sun?
The earth’s rotation axis, which is tilted 23 . 5 ° from the plane of the earth’s orbit, today points to Polaris, the north star. But Polaris has not always been the north star because the earth, like a spinning gyroscope, precesses. That is, a line extending along the earth’s rotation axis traces out a 23.50 cone as the earth precesses with a period of 26,000 years. This occurs because the earth is not a perfect sphere. It has an equatorial bulge , which allows both the moon and the sun to exert a gravitational torque on the earth. Our expression for the precession frequency of a gyroscope can be written Ω = τ / I ω . Although we derived this equation for a specific situation, it’s a valid result, differing by at most a constant close to 1, for the precession of any rotating object. What is the average gravitational torque on the earth due to the moon and the sun?
The earth’s rotation axis, which is tilted
23
.
5
°
from the plane of the earth’s orbit, today points to Polaris, the north star. But Polaris has not always been the north star because the earth, like a spinning gyroscope, precesses. That is, a line extending along the earth’s rotation axis traces out a 23.50 cone as the earth precesses with a period of 26,000 years. This occurs because the earth is not a perfect sphere. It has an equatorial bulge, which allows both the moon and the sun to exert a gravitational torque on the earth. Our expression for the precession frequency of a gyroscope can be written
Ω
=
τ
/
I
ω
. Although we derived this equation for a specific situation, it’s a valid result, differing by at most a constant close to 1, for the precession of any rotating object. What is the average gravitational torque on the earth due to the moon and the sun?
The planet Earth has a semi-major axis of a = 1.00 AU and an orbital period of
P= 1 sidereal year = 365.25 days = 3.156 x 10^7 s. Compute the orbital periods of bodies
orbiting the Sun with each of the following semi-major axes.
a)
a = 0.1 AU
b)
a = 10 AU
c)
a = 100 AU
d)
a = 1000 AU
e)
a = 10,000 AU
1 AU = 1.496 x 10^8 km = 1.496 x 10^11 m = 1.496 x 10^13 cm.
GM(sun) = 1.327 x 10^20 m^3/s^2 = (Newton's Constant) x (Mass of Sun)
%3D
%3D
I measured the angular separation of Jupiter's moons in arcminutes/arcseconds and converted this angle to radians. The conversion factor for degrees to radians was 57.3 degrees per radian. Which unit of measurement is larger? 1 degree or 1 radian?
The solar system has a planet with an orbital period T1b=1.51d and an orbital radius of R1b=1.6456x10^6km. Another planet in the system has an orbital radius of R1f=5.5352x10^6 km. Calculate its orbital period in days.
Chapter 12 Solutions
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
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