Explanation Given: mass is 500 g , angular velocity is 120 rpm , length of the bar is 2.0 m . Formula used: Formula to calculate moment of inertia of the bar, I = 1 12 m l 2 • I is the moment of inertia of the bar. • m is the mass of the bar. • l is the length of the bar. Formula to calculate angular momentum vector of the rotating bar, L → = I ω → • L → is the angular momentum vector. • ω → is the angular velocity of the bar. Calculation: Substitute 500 g for m and 2.0 m for l in the above equation to find I , I = 1 12 [ ( 500 g ) ( 1 kg 10 3 g ) ( 2.0 m ) 2 ] = 0.166 kg ⋅ m 2 Thus, the moment of inertia of the bar is 0.166 kg ⋅ m 2 . Since the bar is rotating in the counterclockwise direction the angular velocity is in the k → direction Formula to calculate angular momentum vector of the rotating bar, L → = I ω → • L → is the angular momentum vector

Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)

4th Edition

ISBN: 9780134110684

Author: Randall D. Knight (Professor Emeritus)

Publisher: PEARSON

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Chapter 12, Problem 44EAP

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The angular momentum vector of the rotating bar

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Chapter 12, Problem 43EAP

Chapter 12, Problem 45EAP

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Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)

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