12th Edition

ISBN: 9780321836960

Author: Mario F. Triola

Publisher: PEARSON

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Probability distributions are of two types, which are continuous probability distributions and discrete probability distributions. A continuous probability distribution contains an infinite number of values. For example, if time is infinite: you could co…

Normal Distribution

Suppose we had to design a bathroom weighing scale, how would we decide what should be the range of the weighing machine? Would we take the highest recorded human weight in history and use that as the upper limit for our weighing scale? This may not be a…

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Textbook Question

Chapter 12, Problem 7CRE

Platelets: Normal Distribution Based on Data Set 1 in Appendix B, assume that adult females have blood platelet counts that are normally distributed with a mean of 280 and a standard deviation of 65. (All units arc in 1000 cells/μL.)

a. Find the probability that a randomly selected adult female has a platelet count greater than 345.
b. Find the probability that a randomly selected adult female has a platelet count between 215 and 345.
c. If 25 adult females arc randomly selected, find the probability that the mean of their platelet counts is less than 319.
d. Find the value of P₈₀, the 80th percentile.

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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Chapter 12, Problem 6CRE

Chapter 12, Problem 8CRE

Chapter 12 Solutions

Elementary Statistics

Ch. 12.2 - In Exercises 1-4, use the following listed chest...Ch. 12.2 - Prob. 2BSC Ch. 12.2 - In Exercises 1-4, use the following listed chest...Ch. 12.2 - Prob. 4BSC Ch. 12.2 - In Exercises 516, use analysis of variance for the...Ch. 12.2 - In Exercises 516, use analysis of variance for the...Ch. 12.2 - Highway Fuel Consumption Data Set 14 in Appendix B...Ch. 12.2 - City Fuel Consumption Data Set 14 in Appendix B...Ch. 12.2 - Head Injury Crash Test Data Exercises 14 use chest...Ch. 12.2 - Pelvis Injury Crash Test Data Exercises 14 use...

Ch. 12.2 - Prob. 11BSC Ch. 12.2 - Prob. 12BSC Ch. 12.2 - Prob. 13BSC Ch. 12.2 - Prob. 14BSC Ch. 12.2 - Prob. 15BSC Ch. 12.2 - Prob. 16BSC Ch. 12.2 - Tukey Test A display of the Bonferroni test...Ch. 12.3 - Prob. 1BSC Ch. 12.3 - Prob. 2BSC Ch. 12.3 - Prob. 3BSC Ch. 12.3 - Prob. 4BSC Ch. 12.3 - Prob. 5BSC Ch. 12.3 - Car Crash Tests The following table lists results...Ch. 12.3 - Prob. 7BSC Ch. 12.3 - Prob. 8BSC Ch. 12.3 - Self-Esteem The following table lists measures of...Ch. 12.3 - Prob. 10BSC Ch. 12.3 - Prob. 11BB Ch. 12 - Measures of Voltage The author measured voltage...Ch. 12 - Prob. 2CQQ Ch. 12 - Prob. 3CQQ Ch. 12 - Prob. 4CQQ Ch. 12 - Prob. 5CQQ Ch. 12 - Prob. 6CQQ Ch. 12 - Prob. 7CQQ Ch. 12 - Prob. 8CQQ Ch. 12 - Using the same results given in Exercise 8, does...Ch. 12 - Prob. 1RE Ch. 12 - Prob. 2RE Ch. 12 - Tar in Cigarettes Data Set 10 in Appendix B...Ch. 12 - Smoking, Body Temperature, Gender The table below...Ch. 12 - Prob. 1CRE Ch. 12 - Prob. 2CRE Ch. 12 - Prob. 3CRE Ch. 12 - Prob. 4CRE Ch. 12 - In Exercises 1-5, refer to the following list of...Ch. 12 - Freshman 15: Correlation/Regression listed below...Ch. 12 - Platelets: Normal Distribution Based on Data Set 1...Ch. 12 - Job Priority Survey USA Today reported about an...Ch. 12 - Prob. 9CRE Ch. 12 - Lottery: Goodness-of-Fit The bars in the histogram...Ch. 12 - Prob. 10CQQ Ch. 12 - Chocolate Chips Revisited The Chapter Problem for...

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Solution Summary: The author explains that the probability of a randomly selected adult female having platelet counts greater than 345 is 0.1587. The formula to convert the x value into z score is:

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