Chapter 1.2, Problem 3WE

To determine

The correct symbol in place of the blank space.

Answer to Problem 3WE

  $\frac{3+2}{3-2}\ne \frac{4+2}{4-2}$

Explanation of Solution

Given:

The given statement is:

  $\frac{3+2}{3-2}\_\_\_\_\_\frac{4+2}{4-2}$

Calculation:

Considering the LHS and RHS separately,

  $\begin{array}{l}LHS:\\ =\frac{3+2}{3-2}\\ =5\\ RHS:\\ =\frac{4+2}{4-2}\\ =\frac{6}{2}\\ =3\\ \text{Therefore,}\\ \frac{3+2}{3-2}\ne \frac{4+2}{4-2}\end{array}$