Algebra and Trigonometry: Structure and Method, Book 2

2000th Edition

ISBN: 9780395977255

Author: MCDOUGAL LITTEL

Publisher: McDougal Littell

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Concept explainers

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Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.

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Question

Chapter 1, Problem 7CR

To determine

The simplified expression.

Expert Solution & Answer

Answer to Problem 7CR

Explanation of Solution

Given:

The given statement is:

(−14+8)−(4−11)

Calculation:

The simplified expression can be obtained as:

=(−14+8)−(4−11)=(−6)−(−7)=−6+7=1

Chapter 1, Problem 6CR

Chapter 1, Problem 8CR

Chapter 1 Solutions

Algebra and Trigonometry: Structure and Method, Book 2

Ch. 1.1 - Prob. 1OE Ch. 1.1 - Prob. 2OE Ch. 1.1 - Prob. 3OE Ch. 1.1 - Prob. 4OE Ch. 1.1 - Prob. 5OE Ch. 1.1 - Prob. 6OE Ch. 1.1 - Prob. 7OE Ch. 1.1 - Prob. 8OE Ch. 1.1 - Prob. 9OE Ch. 1.1 - Prob. 10OE

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Prob. 2CE Ch. 1.5 - Prob. 3CE Ch. 1.5 - Prob. 4CE Ch. 1.6 - Prob. 1OE Ch. 1.6 - Prob. 2OE Ch. 1.6 - Prob. 3OE Ch. 1.6 - Prob. 4OE Ch. 1.6 - Prob. 5OE Ch. 1.6 - Prob. 6OE Ch. 1.6 - Prob. 7OE Ch. 1.6 - Prob. 8OE Ch. 1.6 - Prob. 9OE Ch. 1.6 - Prob. 10OE Ch. 1.6 - Prob. 11OE Ch. 1.6 - Prob. 12OE Ch. 1.6 - Prob. 13OE Ch. 1.6 - Prob. 14OE Ch. 1.6 - Prob. 15OE Ch. 1.6 - Prob. 16OE Ch. 1.6 - Prob. 17OE Ch. 1.6 - Prob. 18OE Ch. 1.6 - Prob. 19OE Ch. 1.6 - Prob. 1WE Ch. 1.6 - Prob. 2WE Ch. 1.6 - Prob. 3WE Ch. 1.6 - Prob. 4WE Ch. 1.6 - Prob. 5WE Ch. 1.6 - Prob. 6WE Ch. 1.6 - Prob. 7WE Ch. 1.6 - Prob. 8WE Ch. 1.6 - Prob. 9WE Ch. 1.6 - Prob. 10WE Ch. 1.6 - Prob. 11WE Ch. 1.6 - Prob. 12WE Ch. 1.6 - Prob. 13WE Ch. 1.6 - Prob. 14WE Ch. 1.6 - Prob. 15WE Ch. 1.6 - Prob. 16WE Ch. 1.6 - Prob. 17WE Ch. 1.6 - Prob. 18WE Ch. 1.6 - Prob. 19WE Ch. 1.6 - Prob. 20WE Ch. 1.6 - Prob. 21WE Ch. 1.6 - Prob. 22WE Ch. 1.6 - Prob. 23WE Ch. 1.6 - Prob. 24WE Ch. 1.6 - Prob. 25WE Ch. 1.6 - Prob. 26WE Ch. 1.6 - Prob. 27WE Ch. 1.6 - 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