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Concept explainers
Draw the structure for each of the following:
- a. isobutyraldehyde
- b. diisopentyl
ketone - c. 3-methylcyclohexanone
- d. 2,4-pentanedione
- e. 4-bromo-3-heptanone
- f. 4-bromohexanal
(a)
![Check Mark](/static/check-mark.png)
Interpretation:
The structure of Isobutyraldehyde has to be drawn.
Concept Introduction:
For any given organic compound name, the corresponding structure can be analysed and drawn by analysing or identifying the following aspects of the name:
- Parent chain.
- Functional group.
- Position of the functional group on the parent chain.
- Alkyl substituent.
- Position of the alkyl substituent on the parent chain.
Answer to Problem 28P
The structure of Isobutyraldehyde is given below:
Explanation of Solution
The compound has aldehyde group that is attached to the isobutyl group.
The structure of isobutyraldehyde is as follows.
(b)
![Check Mark](/static/check-mark.png)
Interpretation:
The structure of diisopentyl ketone has to be drawn.
Concept Introduction:
For any given organic compound name, the corresponding structure can be analysed and drawn by analysing or identifying the following aspects of the name:
- Parent chain.
- Functional group.
- Position of the functional group on the parent chain.
- Alkyl substituent.
- Position of the alkyl substituent on the parent chain.
Answer to Problem 28P
The structure of diisopentyl ketone is given below:
Explanation of Solution
The compound has ketone functional group. Two isopentyl groups are attached to the keto group.
The structure of diisopentyl ketone is as follows.
(c)
![Check Mark](/static/check-mark.png)
Interpretation:
The structure of 3-methylcyclohexanone has to be drawn.
Concept Introduction:
For any given organic compound name, the corresponding structure can be analysed and drawn by analysing or identifying the following aspects of the name:
- Parent chain.
- Functional group.
- Position of the functional group on the parent chain.
- Alkyl substituent.
- Position of the alkyl substituent on the parent chain.
Answer to Problem 28P
The structure of 3-methylcyclohexanoneis given below:
Explanation of Solution
The compound has ketone functional and group and it is cyclohexanone that has one methyl group at 3rd position of the cyclic ring.
The structure of 3-methyl cyclohexanone is as follows.
(d)
![Check Mark](/static/check-mark.png)
Interpretation:
The structure of 2,4-pentanedione has to be drawn.
Concept Introduction:
For any given organic compound name, the corresponding structure can be analysed and drawn by analysing or identifying the following aspects of the name:
- Parent chain.
- Functional group.
- Position of the functional group on the parent chain.
- Alkyl substituent.
- Position of the alkyl substituent on the parent chain.
Answer to Problem 28P
The structure of 2,4-pentanedione is given below:
Explanation of Solution
The compound has two keto functional groups and these are attached to the pentane carbon chain.
The structure of 2,4-pentanedione is as follows:
(e)
![Check Mark](/static/check-mark.png)
Interpretation:
The structure of 4-bromo-3-heptanone has to be drawn.
Concept Introduction:
For any given organic compound name, the corresponding structure can be analysed and drawn by analysing or identifying the following aspects of the name:
- Parent chain.
- Functional group.
- Position of the functional group on the parent chain.
- Alkyl substituent.
- Position of the alkyl substituent on the parent chain.
Answer to Problem 28P
The structure of 4-bromo-3-heptanone is given below:
Explanation of Solution
The compound has keto functional group and it is attached to the heptane carbon chain. At the 4th position of the carbon chain has bromine attachment.
(f)
![Check Mark](/static/check-mark.png)
Interpretation:
The structure of 4-bromohexenal has to be drawn.
Concept Introduction:
For any given organic compound name, the corresponding structure can be analysed and drawn by analysing or identifying the following aspects of the name:
- Parent chain.
- Functional group.
- Position of the functional group on the parent chain.
- Alkyl substituent.
- Position of the alkyl substituent on the parent chain.
Answer to Problem 28P
The structure of 4-bromohexenal is given below:
Explanation of Solution
The compound has bromine functional group at the 4th position from the aldehyde functional group on the hexane parent chain.
The structure of 4-bromohexenal is as follows:
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Chapter 12 Solutions
Essential Organic Chemistry Study Guide & Solution Manual, Books a la Carte Edition
- 10- 4000 20 20 30- %Reflectance 60 50- 09 60- 40- Date: Thu Feb 06 17:30:02 2025 (GMT-05:0(UnknownP Scans: 8 Resolution: 2.000 70 70 88 80 3500 3000 2500 90 100 00 Wavenumbers (cm-1) 2000 1500 2983.10 2359.13 1602.52 1584.22 1451.19 1391.87 1367.07 1314.37 1174.34 1070.13 1027.33 1714.16 1269.47 1000 1106.08 1001.14 937.02 873.60 850.20 780.22 686.91 674.38 643.09 617.98 02/06/25 16:38:20arrow_forwardd. Draw arrow-pushing mechanism for an enzymatic retro-aldol reaction of the following hexose. Use B: and/or HA as needed. OH OH سية HO OH OHarrow_forward4. Calculate the wavelength of a photon needed to excite a transition between neighbouring energy levels of a harmonic oscillator of effective mass equal to that of an oxygen atom and with a force constant of 544 N m¹.arrow_forward
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- Add curved arrows to show the forming and breaking of bonds in the reaction below. :Br: H 2 Add/Remove step ☑ H-Br: G હે Parrow_forwardPlease correct answer and don't use hand ratingarrow_forwardSafari File Edit View History Bookmarks Window Help く < mylabmastering.pearson.com Wed Feb 12 8:44 PM ✩ + Apple Q Bing Google SignOutOptions M Question 36 - Lab HW BI... P Pearson MyLab and Mast... P Course Home Error | bartleby b Answered: If the biosynth... Draw a free-radical mechanism for the following reaction, forming the major monobromination product: ScreenPal - 2022 CHEM2... Access Pearson 2 CH3 Br-Br CH H3 Draw all missing reactants and/or products in the appropriate boxes by placing atoms on the canvas and connecting them with bonds. Add charges where needed. Electron- flow arrows should start on the electron(s) of an atom or a bond and should end on an atom, bond, or location where a new bond should be created. Include all free radicals by right-clicking on an atom on the canvas and then using the Atom properties to select the monovalent radical. ▸ View Available Hint(s) 0 2 DE [1] H EXP. CONT. H. Br-Br H FEB 12arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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