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Concept explainers
Interpretation:
The molecule which exists as solid at room temperature is to be determined out of the four given options.
Concept Introduction:
A hydrocarbon is organic compound consisting entirely of hydrogen and carbon.
Butane and hexane both are hydrocarbon. Butane is a four-carbon
The temperature at which the vapour pressure of the liquid is equal to the pressure exerted on the liquid by the surrounding atmosphere is called boiling point.
Boiling point of a molecule depends on the intermolecular forces and thermal energy.
Intermolecular forces are of two types: dispersion forces and dipole forces.
Dispersion forces are possessed by all the atoms or molecules, which depend on the molar mass.
Dipole forces exist between polar molecules, which depend on the polarity of the molecules.
Intermolecular forces keep the molecules together. Greater the intermolecular force, higher is the boiling point.
All atoms and molecules possess dispersion forces which depend upon their molar mass.
Polar molecules possess dipole forces between them which depend upon the polarity of the molecules.
A molecular formula consists of the
Dispersion forces are weak intermolecular forces and are considered van der waals forces.
Temporary dipoles can occur in non-polar molecules when the electrons that constantly orbit the nucleus occupy a similar location by chance.
Higher the molar mass, higher is the magnitude of the dispersion forces, and hence, higher is the boiling point.
Molecules which have lower molar masses have lower dispersion forces because dispersion force is directly proportional to the molar mass.
Molecules which have higher molar masses have higher dispersion forces.
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Chapter 12 Solutions
Chemistry In Focus
- compared t-critical with t-calculated and 95% confidence interval to answer this questionarrow_forwardComparing two means. Horvat and co-workers used atomic absorption spectroscopy to determine the concentration of Hg in coal fly ash. Of particular interest to the authors was developing an appropriate procedure for digesting samples and releasing the Hg for analysis. As part of their study they tested several reagents for digesting samples. Their results using HNO3 and using a 1+3 mixture of HNO3 and HCl are shown here. All concentrations are given as ppb Hg sample. HNO3: 161, 165, 160, 167, 166 1+3 HNO3–HCl: 159, 145, 140, 147, 143, 156 Determine whether there is a significant difference between these methods at the 95% confidence interval.arrow_forwardComparison of experimental data to “known” value. Monna and co-workers used radioactive isotopes to date sediments from lakes and estuaries.21 To verify this method they analyzed a 208Po standard known to have an activity of 77.5 decays/min, obtaining the following results. 77.09, 75.37, 72.42, 76.84, 77.84, 76.69, 78.03, 74.96, 77.54, 76.09, 81.12, 75.75 Do the results differ from the expected results at the 95% confidence interval?arrow_forward
- Explain the difference between the propagated uncertainty and the standard deviation. Which number would you use to describe the uncertainty in the measurement? if the standard deviation is 0.01 and the propagated uncertainty is 0.03arrow_forwardPropagation of uncertainty. Find the absolute and percent relative uncertainty assuming the ±-values are random error. 7.65±0.04 + 5.28±0.02 – 1.12±0.01 85.6±0.9 × 50.2±0.7 ÷ 13.8±0.5 [4.88±0.07 + 3.22±0.05] / 1.53±0.02arrow_forwardExplain the difference between the propagated uncertainty and the standard deviation. Which number would you use to describe the uncertainty in the measurement?arrow_forward
- Circle the compound in each pair where the indicated bond vibrates at higher frequency. WHY IS THIS? Provide thorough explanation to tie topic.arrow_forwardHow can you distinguish between each pair of compounds below using IR? Cite a bond and frequency that can be used to distinguish. Provide thorough steps and explanation.arrow_forwardPropagation of uncertainty. Find the absolute and percent relative uncertainty assuming the ±-values are random error. 65±0.04 + 5.28±0.02 – 1.12±0.01 6±0.9 × 50.2±0.7 ÷ 13.8±0.5 [4.88±0.07 + 3.22±0.05] / 1.53±0.02arrow_forward
- Match to correct spectrum and explain the bonds and frequencies used to tell what spectrum connected to the given option. Thanks.arrow_forwardDraw the virtual orbitals for the planar and pyramidal forms of CH3 and for the linear and bent forms of CH2arrow_forwardQ2: Draw the molecules based on the provided nomenclatures below: (2R,3S)-2-chloro-3-methylpentane: (2S, 2R)-2-hydroxyl-3,6-dimethylheptane:arrow_forward
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