Interpretation:
The steps that should be taken to minimize the intake of lead from tap water are to be determined.
Concept Introduction:
Water is a common liquid that is present on the Earth.
It is also known as universal solvent. It can dissolve a wide range of organic and inorganic solutes.
Water is vital for the existence of all living animals. Without water, no life form can exist, it constitutes an important part of rivers, lakes, streams, clouds, snow and ice.
Water is truly an unusual molecule such that being a low molar mass compound, it exists as a liquid at room temperature and has an anonymously high boiling point.
Ice floats on water because it has a lower density than water.
Water contains some unwanted particles which can lead to diseases and other hostile effects on human health.
Numerous types of micro-organisms such as bacteria are present in water, which contaminate the water.
Biological contaminants: Some microbes can live in water and can cause various diseases like cholera, dysentery, and so on. Two examples of such microbes are Giardia and Legionella.
Inorganic contaminants: Some inorganic molecules can dissolve in water and make it impotable (not suited for drinking). Two examples of such molecules are Nitrates and Asbestos.
Organic contaminants: Some organic molecules can dissolve in water and makes it impotable (not suited for drinking). Two examples of such molecules are chlorohydrocarbons (volatile) and ethylbenzene (non-volatile).
Radioactive contaminants: Some radioactive elements can dissolve in water and make it impotable (not suited for drinking). Two examples of such elements are Uranium and Radium.
Contaminants that pose immediate health risks are the biological contaminants and inorganic contaminants because they get immediately dissolved in blood and starts reacting with it.
Contaminants that can be eliminated by boiling are the biological contaminants because the microbes can be killed by increasing the temperature.
Hot water dissolves lead more than cold water does.
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Chapter 12 Solutions
Chemistry In Focus
- 1. For the four structures provided, Please answer the following questions in the table below. a. Please draw π molecular orbital diagram (use the polygon-and-circle method if appropriate) and fill electrons in each molecular orbital b. Please indicate the number of π electrons c. Please indicate if each molecule provided is anti-aromatic, aromatic, or non- aromatic TT MO diagram Number of π e- Aromaticity Evaluation (X choose one) Non-aromatic Aromatic Anti-aromatic || ||| + IVarrow_forward1.3 grams of pottasium iodide is placed in 100 mL of o.11 mol/L lead nitrate solution. At room temperature, lead iodide has a Ksp of 4.4x10^-9. How many moles of precipitate will form?arrow_forwardQ3: Circle the molecules that are optically active: ДДДДarrow_forward
- 6. How many peaks would be observed for each of the circled protons in the compounds below? 8 pts CH3 CH3 ΤΙ A. H3C-C-C-CH3 I (₁₁ +1)= 7 H CI B. H3C-C-CI H (3+1)=4 H LIH)=2 C. (CH3CH2-C-OH H D. CH3arrow_forwardNonearrow_forwardQ1: Draw the most stable and the least stable Newman projections about the C2-C3 bond for each of the following isomers (A-C). Are the barriers to rotation identical for enantiomers A and B? How about the diastereomers (A versus C or B versus C)? H Br H Br (S) CH3 (R) CH3 H3C (S) H3C H Br Br H A C enantiomers H Br H Br (R) CH3 H3C (R) (S) CH3 H3C H Br Br H B D identicalarrow_forward
- 2. Histamine (below structure) is a signal molecule involved in immune response and is a neurotransmitter. Histamine features imidazole ring which is an aromatic heterocycle. Please answer the following questions regarding Histamine. b a HN =N C NH2 a. Determine hybridization of each N atom (s, p, sp, sp², sp³, etc.) in histamine N-a hybridization: N-b hybridization: N-c hybridization: b. Determine what atomic orbitals (s, p, sp, sp², sp³, etc.) of the lone pair of each N atom resided in N-a hybridization: N-b hybridization: N-c hybridization:arrow_forwardNonearrow_forward29. Use frontier orbital analysis (HOMO-LUMO interactions) to decide whether the following dimerization is 1) thermally allowed or forbidden and 2) photochemically allowed or forbidden. +arrow_forward
- 30.0 mL of 0.10 mol/L iron sulfate and 20.0 mL of 0.05 mol/L of silver nitrate solutions are mixed together. Justify if any precipitate would formarrow_forwardDoes the carbonyl group first react with the ethylene glycol, in an intermolecular reaction, or with the end alcohol, in an intramolecular reaction, to form a hemiacetal? Why does it react with the alcohol it does first rather than the other one? Please do not use an AI answer.arrow_forwardThe number of noncyclic isomers that have the composition C4H8Owith the O as part of an OH group, counting a pair of stereoisomers as1, is A. 8; B. 6; C. 9; D. 5; E. None of the other answers is correct.arrow_forward
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