
(a) Interpretation:
The statement "In liver, glucagon stimulates glycogen breakdown via camp. Although you might expect glucagon to stimulate catabolism of the glucose formed as well, glucagon inhibits glycolysis and stimulates gluconeogenesis in liver" should be explained.
Concept introduction:
When there is glycogen breakdown under the influence of glycogen, it releases glucose. Enzyme glucose -6-phosphate is essential for the formation of glucose by liver which it transports to other tissues. Phosphorylase kinase is an enzyme that donates phosphorous to convert the phosphorylase b (inactive) to a (active).
(b) Interpretation:
The statement "an individual with glucose − 6- phosphate deficiency suffers from chronic hypoglycemia" should be explained.
(c) Interpretation:
The statement "the action of phosphorylase kinase simultaneously activates glycogen breakdown and inhibits glycogen synthesis" should be explained.
(d) Interpretation:
The statement "the presence in liver of glucose-6-phosphate is essential to the function of the liver in synthesizing glucose for use by other tissues" should be explained.

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Chapter 12 Solutions
Biochemistry: Concepts and Connections
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- 1. Which one is the major organic product obtained from the following aldol condensation? O NaOH, H₂O heat A B C D Earrow_forwardAn organic chemist ordered the wrong item. She wanted to obtain 1-hydroxy-2-butanone, butinstead ordered 2-hydroxybutyraldehyde. As a good biochemist, show how the organic chemistcould use biological catalysis to make her desired compound. Please show the mechanism by drawing.arrow_forwardShow the fate of the hydrogen on carbon-2 of glucose. Please draw out the structure using curve arrows to show electron flow.arrow_forward
- 3. Which one of the compounds below is the major product formed by the reaction sequence shown here? CH3 + CH3NO2 NaOH H2, Ni ? nitromethane acetophenone OH OH HO HN- u x x x x Ph A HO -NH2 HO H Ph Ph Ph N- H B Ph NH2 D Earrow_forward4. Only ONE of the five compounds below can be prepared by an aldol condensation in which a single carbonyl compound is treated with base. Which one is it? To solve this problem, reverse the aldol condensation that formed each of these molecules to find out what two molecules came together to make the products. The one in which the two molecules are identical is the answer. Ph Ph ཚིག གནས ག ནཱ ཀ ན ཀནཱ A Ph H B Ph Ph H D Ph. Ph Ph E Harrow_forward5. Which one is the major organic product obtained from the following reaction sequence? First, equimolar amounts of cyclopentanone and LDA are mixed at -78°C. Then propionaldehyde (propanal) is added. Addition of aqueous acid completes the process. LDA, -78°C. 1. 2. H₂O* H A B H 0 D H H Earrow_forward
- 2. Which one is the major organic product obtained from the following reaction? NaOH, H₂O heat A B C D Earrow_forwardCH3CH2CHO + propanal PhCH2CHO 2-phenylacetaldehyde mixture of four products NaOH 10. In the crossed aldol reaction of propanal and 2-phenylacetaldehyde shown above, a mixture of four products will be formed. Which ONE of the compounds below will NOT be formed in this crossed aldol reaction? OH Ph A H OH OH Ph H B OH OH H H H Ph Ph C Ph D Earrow_forwardAn organic chemist ordered the wrong item. She wanted to obtain 1-hydroxy-2-butanone, butinstead ordered 2-hydroxybutyraldehyde. As a good biochemist, show how the organic chemistcould use biological catalysis to make her desired compound.arrow_forward
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