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Concept explainers
The graph shows the ideal gas law relationship (PV =nRT) between volume (V) and temperature (T).
- a. What are the units of the slope (0.0175)?
- b. If the tank has a pressure of 2.4 atmospheres and is filled with nitrogen (formula, N2; molecular weight, 28 grams per mole), what is the mass of gas in the tank in units of grams?
- c.
If the tank is filled with 20 grams of oxygen (formula, o2; molecular weight, 32 grams per mole), what is the pressure of the tank (P) in units of atmospheres?
a.
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Find the slope units.
Answer to Problem 1ICA
The units of slope is
Explanation of Solution
Calculation:
Refer to the graph in the respective question. The expression is,
Rearrange the expression.
From the graph, the unit of volume (V) is L and temperature (T) is K. Therefore, the unit of slope (0.0175) is
Conclusion:
Thus, the units of slope is
b.
![Check Mark](/static/check-mark.png)
Find the mass of gas in terms of grams.
Answer to Problem 1ICA
The mass of nitrogen gas in terms of grams is 14.4 g.
Explanation of Solution
Given data:
Molecular weight (MW) of nitrogen is 28 grams per mole.
Pressure (P)is 2.4 atmospheres.
Formula used:
Consider the ideal gas law relationship.
Here,
Calculation:
Refer to the graph in the respective question. The expression is,
Modify equation (1) as follows.
Substitute
Substitute 2.4 atm for P and
Consider the general expression for mass in terms of molecular weight.
Substitute
Conclusion:
Thus, the mass of nitrogen gas in terms of grams is 14.4 g.
c.
![Check Mark](/static/check-mark.png)
Find the pressure of tank in terms of atmospheres.
Answer to Problem 1ICA
The pressure of tank in terms of atmospheres is 3.0 atm.
Explanation of Solution
Given data:
Molecular weight (MW) of oxygen is 32 grams per mole.
Mass of oxygen (m)is 20 grams.
Calculation:
Refer to the graph in the respective question.
Modify equation (2).
Substitute 20 g for
Modify equation (1).
Substitute
Substitute 0.625 mol for n and
Conclusion:
Thus, the pressure of tank in terms of atmospheres is 3.0 atm.
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Chapter 12 Solutions
Thinking Like an Engineer: An Active Learning Approach (4th Edition)
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