Solve the linear systems in Exercises 13 through 17. You may use technology. 17. | 2 x 1 + 4 x 2 + 3 x 3 + 5 x 4 + 6 x 5 = 37 4 x 1 + 8 x 2 + 7 x 3 + 5 x 4 + 2 x 5 = 74 − 2 x 1 − 4 x 2 + 3 x 3 + 4 x 4 − 5 x 5 = 20 x 1 + 2 x 2 + 2 x 3 − x 4 + 2 x 5 = 26 5 x 1 − 10 x 2 + 4 x 3 + 6 x 4 + 4 x 5 = 24 |
Solve the linear systems in Exercises 13 through 17. You may use technology. 17. | 2 x 1 + 4 x 2 + 3 x 3 + 5 x 4 + 6 x 5 = 37 4 x 1 + 8 x 2 + 7 x 3 + 5 x 4 + 2 x 5 = 74 − 2 x 1 − 4 x 2 + 3 x 3 + 4 x 4 − 5 x 5 = 20 x 1 + 2 x 2 + 2 x 3 − x 4 + 2 x 5 = 26 5 x 1 − 10 x 2 + 4 x 3 + 6 x 4 + 4 x 5 = 24 |
Solution Summary: The author explains that a matrix is in reduced row-echelon form if it satisfies all of the following conditions.
Solve the linear systems in Exercises 13 through 17. You may use technology.
17.
|
2
x
1
+
4
x
2
+
3
x
3
+
5
x
4
+
6
x
5
=
37
4
x
1
+
8
x
2
+
7
x
3
+
5
x
4
+
2
x
5
=
74
−
2
x
1
−
4
x
2
+
3
x
3
+
4
x
4
−
5
x
5
=
20
x
1
+
2
x
2
+
2
x
3
−
x
4
+
2
x
5
=
26
5
x
1
−
10
x
2
+
4
x
3
+
6
x
4
+
4
x
5
=
24
|
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P1:
P2:
P3:
P4:
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