
Concept explainers
(a)
Interpretation:
The dipole moment arrow is to be drawn for the given C-F bond.
Concept introduction:
Dipole moment arrows are drawn from the atom with less electronegativity to atom with more electronegativity.
(a)

Answer to Problem 17A
Explanation of Solution
Fluorine is more electronegative than carbon because left to right electronegativity increases. So, arrow will be from carbon to fluorine.
(b)
Interpretation:
The dipole moment arrow is to be drawn for the given Si-C bond.
Concept introduction:
Dipole moment arrows are drawn from the atom with less electronegativity to atom with more electronegativity.
(b)

Answer to Problem 17A
Explanation of Solution
Carbon is more electronegative than silicon because down the group electronegativity decreases. So, arrow will be from carbon to silicon.
(c)
Interpretation:
The dipole moment arrow is to be drawn for the C-O bond.
Concept introduction:
Dipole moment arrows are drawn from the atom with less electronegativity to atom with more electronegativity.
(c)

Answer to Problem 17A
Explanation of Solution
Oxygen is more electronegative than carbon because left to right electronegativity increases. So, arrow will be from carbon to oxygen.
(d)
Interpretation:
The dipole moment arrow is to be drawn for the given B-C bond.
Concept introduction:
Dipole moment arrows are drawn from the atom with less electronegativity to atom with more electronegativity.
(d)

Answer to Problem 17A
Explanation of Solution
Carbon is more electronegative than boron because left to right electronegativity increases. So, arrow will be from carbon to boron.
Chapter 12 Solutions
World of Chemistry, 3rd edition
- A mixture of C7H12O2, C9H9OCl, biphenyl and acetone was put together in a gas chromatography tube. Please decide from the GC resutls which correspond to the peak for C7,C9 and biphenyl and explain the reasoning based on GC results. Eliminate unnecessary peaks from Gas Chromatography results.arrow_forwardIs the molecule chiral, meso, or achiral? CI .CH3 H₂C CIarrow_forwardPLEASE HELP ! URGENT!arrow_forward
- Identify priority of the substituents: CH3arrow_forwardHow many chiral carbons are in the molecule? OH F CI Brarrow_forwardA mixture of three compounds Phen-A, Acet-B and Rin-C was analyzed using TLC with 1:9 ethanol: hexane as the mobile phase. The TLC plate showed three spots of R, 0.1 and 0.2 and 0.3. Which of the three compounds (Phen-A; Acet-B or Rin-C) would have the highest (Blank 1), middle (Blank 2) and lowest (Blank 3) spot respectively? 0 CH: 0 CH, 0 H.C OH H.CN OH Acet-B Rin-C phen-A A A <arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





