Chapter 1.2, Problem 12CYU

To determine

To Evaluate: The expression $\frac{b\left(9-c\right)}{a^2}$

Answer to Problem 12CYU

  $\frac{b\left(9-c\right)}{a^2}=\frac{3}{8}$

Explanation of Solution

Given information:

The expression $\frac{b\left(9-c\right)}{a^2}$ and value of $a=4,b=6\&c=8$

Concept and Formula Used:

Rule of exponent and addition and subtraction.

  $a^n=a\times a\times a\times \mathrm{..................}n\text{ times}\text{.}$

BODMAS rule

Calculation:

The given expression is $\frac{b\left(9-c\right)}{a^2}$

Putting the values of $a=4,b=6\&c=8$ in the expression

  $\begin{array}{l}\frac{b\left(9-c\right)}{a^2}=\frac{6\left(9-8\right)}{4^2}\\ \text{Solving the expression in the grouping by subtracting}\\ \frac{b\left(9-c\right)}{a^2}=\frac{6\left(1\right)}{4^2}\\ \text{Multiply the numbers in the numerator}\\ \frac{b\left(9-c\right)}{a^2}=\frac{6}{4^2}\\ \text{Evaluate the power in the denominator}\\ \frac{b\left(9-c\right)}{a^2}=\frac{6}{16}\\ \text{Simplifying}\\ \frac{b\left(9-c\right)}{a^2}=\frac{3}{8}\end{array}$

Conclusion:

  $\frac{b\left(9-c\right)}{a^2}=\frac{3}{8}$