Chapter 12, Problem 12.89QP

Interpretation Introduction

Interpretation:

Percent ionisation of $\text{0}\text{.10M}$ monoprotic acid $\text{HA}$ has to be determined.

Concept introduction:

Osmotic pressure is the pressure that is needed to stop osmosis. Osmotic pressure of the solution is directly proportional to the concentration of the solution. We can calculate osmotic pressure by using this formula is given by,

Osmotic pressure $\text{(π) = MRT}$

Where,

$\text{M-}$ Molarity of the solution $\left(\text{mol/L}\right)$

$\text{R-}$ Ideal gas constant ($0.08206{\text{L atm mol}}^{\text{-1}}{\text{K}}^{\text{-1}}$)

$\text{T-}$ Temperature in Kelvin

Percent by mass: It is the ratio of solute mass to the solution mass which finally multiplied by $\text{100}$. The formula for percent by mass calculation is as follows,

$\begin{array}{l}\text{Percent mass =}\frac{\text{Mass}\text{of}\text{solute}}{\text{Mass of solution}}\text{×100\%}\\ \text{Mass of solution = Mass of solute + Mass of solvent}\end{array}$