(a)
Interpretation:
Three beakers of same solution ‘A’, ‘B’ and ‘C’ made of water and non-volatile solute are given –
Figure 1
The solution having higher vapor pressure has to be identified.
Concept Introduction:
Vapor pressure of a substance is known as the pressure exerted by molecules on the vapor phase when they are in equilibrium with their actual phase which can be liquid or solid.
A substance is said to be volatile if it vaporizes readily at room temperature itself. Such substances have high vapor pressure as most of its molecules tend to exist in vapor phase. A substance is said to be non-volatile if it doesn’t vaporize spontaneously and remains stable.
Vapor pressure of a volatile solvent can be lowered by addition of a non-volatile solute. Raoult’s law deals with the vapor pressure of pure solvents and solution which states –
Partial pressure of solvent is equivalent to the product of vapor pressure of the solvent in its pure state and mole fraction of solvent in the solution. It is expressed as,
Where,
When the solute is non-volatile, the vapor pressure of the whole solution is equal to
The lowering of vapor pressure of the solvent due to the addition of non-volatile solute is expressed as,
Where,
(b)
Interpretation:
Three beakers of same solution ‘A’, ‘B’ and ‘C’ made of water and non-volatile solute are given –
Figure 1
The solution with lowest boiling point has to be identified.
Concept Introduction:
Boiling point of a liquid substance is defined as the temperature at which the vapor pressure of the liquid becomes equal to the atmospheric pressure.
Boiling point of a substance can be determined by the formula,
Where,
(c)
Interpretation:
Three beakers of same solution ‘A’, ‘B’ and ‘C’ made of water and non-volatile solute are given –
Figure 1
A laboratory procedure to make all these three solutions to have same freezing point has to be described.
Concept Introduction:
Freezing point of the substance is temperature at which liquid substance remains in equilibrium with solid substance.
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Chapter 12 Solutions
General Chemistry - Standalone book (MindTap Course List)
- Equal numbers of moles of two soluble, substances, substance A and substance B, are placed into separate 1.0-L samples of water. a The water samples are cooled. Sample A freezes at 0.50C, and Sample B freezes at l.00C. Explain how the solutions can have different freezing points. b You pour 500 mL of the solution containing substance B into a different beaker. How would the freezing point of this 500-mL portion of solution B compare to the freezing point of the 1.0-L sample of solution A? c Calculate the molality of the solutions of A and B. Assume that i = 1 for substance A. d If you were to add an additional 1.0 kg of water to solution B, what would be the new freezing point of the solution? Try to write an answer to this question without using a mathematical formula. e What concentration (molality) of substances A and B would result in both solutions having a freezing point of 0.25C? f Compare the boiling points, vapor pressure, and osmotic pressure of the original solutions of A and B. Dont perform the calculations; just state which is the greater in each ease.arrow_forwardThe following diagrams show varying amounts of the same solute (the red spheres) in varying amounts of solution. a. In which of the diagrams is the solution concentration the largest? b. In which two of the diagrams are the solution concentrations the same?arrow_forwardYou have read that adding a solute to a solvent can both increase the boiling point and decrease the freezing point. A friend of yours explains it to you like this: The solute and solvent can be like salt in water. The salt gets in the way of freezing in that it blocks the water molecules from joining together. The salt acts like a strong bond holding the water molecules together so that it is harder to boil. What do you say to your friend?arrow_forward
- In your own words, explain why (a) seawater has a lower freezing point than fresh water. (b) salt is added to the ice in an ice cream maker to freeze the ice cream faster.arrow_forwardConsider two hypothetical pure substances, AB(s) and XY(s). When equal molar amounts of these substances are placed in separate 500-mL samples of water, they undergo the following reactions: AB(s)A+(aq)+B(aq)XY(s)XY(aq) a Which solution would you expect to have the lower boiling point? Why? b Would you expect the vapor pressures of the two solutions to be equal? If not, which one would you expect to have the higher vapor pressure? c Describe a procedure that would make the two solutions have the same boiling point. d If you took 250 mL of the AB(aq) solution prepared above, would it have the same boiling point as the original solution? Be sure to explain your answer. e The container of XY(aq) is left out on the bench top for several days, which allows some of the water to evaporate from the solution. How would the melting point of this solution compare to the melting point of the original solution?arrow_forwardIn your own words, explain (a) why seawater has a lower freezing point than fresh water. (b) why one often obtains a grainy product when making fudge (a supersaturated sugar solution). (c) why the concentrations of solutions used for intravenous feeding must be controlled carefully. (d) why fish in a lake (and fishermen) seek deep, shaded places during summer afternoons. (e) why champagne fizzes in a glass.arrow_forward
- How do solutions differ from compounds? From other mixtures?arrow_forwardHow can it be demonstrated that colloidal particles are electrically charged?arrow_forwardRefer to Figure 13.10 ( Sec. 13-4b) to determine whether these situations would result in an unsaturated, saturated, or supersaturated solution. 120. g RbCl is added to 100. g H2O at 50 °C. 30. g KCl is dissolved in 100. g H2O at 70 °C. 20. g NaCl is dissolved in 50. g H2O at 60 °C. Figure 13.10 Solubility of ionic compounds versus temperature.arrow_forward
- Every pure substance has a definite and fixed set of physical and chemical properties. A solution is prepared by dissolving one pure substance in another. Is it reasonable to expect that the solution will also have a definite and fixed set of properties that are different from the properties of either component? Explain your answer.arrow_forwardConsider the following aqueous solutions: (i) 0.20 m HOCH2CH2OH (nonvolatile, nonelectrolyte); (ii) 0.10 m CaCl2 (iii) 0.12 m KBr; and (iv) 0.12 m Na2SO4. (a) Which solution has the highest boiling point? (b) Which solution has the lowest freezing point? (c) Which solution has the highest water vapor pressure?arrow_forward
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