Chapter 12, Problem 12.22QP

Interpretation Introduction

Interpretation:

Mole fraction of copper (II) nitrate in aqueous solution is $\mathrm{0.135.}$ Molality of the solution has to be calculated and the right answer has to be chosen from the following options –

 (a) $7.49m$  (b) $8.01m$

 (c) $8.66m$ (d) $9.34m$ (e) $8.09m$

Concept Introduction:

Molality is one of the parameters used to express concentration of a solution.  It is expressed as,

$\text{Molality = }\frac{number\text{ of }molesof\text{ solute}}{mass\text{ of solvent in kg}}$

A solution is at least made up of two components.  Mole fraction of a component in the solution correlates to the ratio of number of moles of that component to the total number of moles.  It is expressed as,

$\text{Mole fraction = }\frac{number\text{ of moles of a component}}{total\text{ number of moles in the solution}}$