Mass balance for CaF 2 in water has to be written. Concept Introduction: Mass balance equation represents net quantity of all such species in solution that have specific atoms must remain equal to total quantity of atoms added or delivered to the system initially. For example, if 0.020 mol of acetic acid has been dissolved in 1 L solvent to form 0.020 M CH 3 COOH solution, then after dissolution, amount of unionized and ionized acetic acid must remain equal to 0.020 M . 0.020 M = [ CH 3 COO − ] + [ CH 3 COOH ] For any systematic equilibrium, there might be more than one mass balance equations unlike charge balance equation. Such equations are governed by possible product species.

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Answer 1

Question

Chapter 12, Problem 12.28P

(a)

Interpretation Introduction

Interpretation:

Mass balance for CaF2 in water has to be written.

Concept Introduction:

Mass balance equation represents net quantity of all such species in solution that have specific atoms must remain equal to total quantity of atoms added or delivered to the system initially.

For example, if 0.020 mol of acetic acid has been dissolved in 1 L solvent to form 0.020 M CH3COOH solution, then after dissolution, amount of unionized and ionized acetic acid must remain equal to 0.020 M.

0.020 M=[CH3COO−]+[CH3COOH]

For any systematic equilibrium, there might be more than one mass balance equations unlike charge balance equation. Such equations are governed by possible product species.

(b)

Interpretation Introduction

Interpretation:

Mass balance equation for CaF2 in water when additional species HF and HF2− are also formed have to be written.

Concept Introduction:

Refer to part (a).

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Answer 2

Question

Chapter 12, Problem 12.28P

(a)

Interpretation Introduction

Interpretation:

Mass balance for CaF2 in water has to be written.

Concept Introduction:

Mass balance equation represents net quantity of all such species in solution that have specific atoms must remain equal to total quantity of atoms added or delivered to the system initially.

For example, if 0.020 mol of acetic acid has been dissolved in 1 L solvent to form 0.020 M CH3COOH solution, then after dissolution, amount of unionized and ionized acetic acid must remain equal to 0.020 M.

0.020 M=[CH3COO−]+[CH3COOH]

For any systematic equilibrium, there might be more than one mass balance equations unlike charge balance equation. Such equations are governed by possible product species.

(b)

Interpretation Introduction

Interpretation:

Mass balance equation for CaF2 in water when additional species HF and HF2− are also formed have to be written.

Concept Introduction:

Refer to part (a).

Expert Solution & Answer

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Answer 3

Question

Chapter 12, Problem 12.28P

(a)

Interpretation Introduction

Interpretation:

Mass balance for CaF2 in water has to be written.

Concept Introduction:

Mass balance equation represents net quantity of all such species in solution that have specific atoms must remain equal to total quantity of atoms added or delivered to the system initially.

For example, if 0.020 mol of acetic acid has been dissolved in 1 L solvent to form 0.020 M CH3COOH solution, then after dissolution, amount of unionized and ionized acetic acid must remain equal to 0.020 M.

0.020 M=[CH3COO−]+[CH3COOH]

For any systematic equilibrium, there might be more than one mass balance equations unlike charge balance equation. Such equations are governed by possible product species.

(b)

Interpretation Introduction

Interpretation:

Mass balance equation for CaF2 in water when additional species HF and HF2− are also formed have to be written.

Concept Introduction:

Refer to part (a).

Expert Solution & Answer

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Answer 4

Question

Chapter 12, Problem 12.28P

(a)

Interpretation Introduction

Interpretation:

Mass balance for CaF2 in water has to be written.

Concept Introduction:

Mass balance equation represents net quantity of all such species in solution that have specific atoms must remain equal to total quantity of atoms added or delivered to the system initially.

For example, if 0.020 mol of acetic acid has been dissolved in 1 L solvent to form 0.020 M CH3COOH solution, then after dissolution, amount of unionized and ionized acetic acid must remain equal to 0.020 M.

0.020 M=[CH3COO−]+[CH3COOH]

For any systematic equilibrium, there might be more than one mass balance equations unlike charge balance equation. Such equations are governed by possible product species.

(b)

Interpretation Introduction

Interpretation:

Mass balance equation for CaF2 in water when additional species HF and HF2− are also formed have to be written.

Concept Introduction:

Refer to part (a).

Expert Solution & Answer

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Answer 5

Chapter 12, Problem 12.28P

(a)

Interpretation Introduction

Interpretation:

Mass balance for CaF2 in water has to be written.

Concept Introduction:

Mass balance equation represents net quantity of all such species in solution that have specific atoms must remain equal to total quantity of atoms added or delivered to the system initially.

For example, if 0.020 mol of acetic acid has been dissolved in 1 L solvent to form 0.020 M CH3COOH solution, then after dissolution, amount of unionized and ionized acetic acid must remain equal to 0.020 M.

0.020 M=[CH3COO−]+[CH3COOH]

For any systematic equilibrium, there might be more than one mass balance equations unlike charge balance equation. Such equations are governed by possible product species.

(b)

Interpretation Introduction

Interpretation:

Mass balance equation for CaF2 in water when additional species HF and HF2− are also formed have to be written.

Concept Introduction:

Refer to part (a).

Answer 6

Chapter 12, Problem 12.28P

(a)

Interpretation Introduction

Interpretation:

Mass balance for CaF2 in water has to be written.

Concept Introduction:

Mass balance equation represents net quantity of all such species in solution that have specific atoms must remain equal to total quantity of atoms added or delivered to the system initially.

For example, if 0.020 mol of acetic acid has been dissolved in 1 L solvent to form 0.020 M CH3COOH solution, then after dissolution, amount of unionized and ionized acetic acid must remain equal to 0.020 M.

0.020 M=[CH3COO−]+[CH3COOH]

For any systematic equilibrium, there might be more than one mass balance equations unlike charge balance equation. Such equations are governed by possible product species.

Answer 7

Chapter 12, Problem 12.28P

(a)

Interpretation Introduction

Interpretation:

Mass balance for CaF2 in water has to be written.

Concept Introduction:

Mass balance equation represents net quantity of all such species in solution that have specific atoms must remain equal to total quantity of atoms added or delivered to the system initially.

For example, if 0.020 mol of acetic acid has been dissolved in 1 L solvent to form 0.020 M CH3COOH solution, then after dissolution, amount of unionized and ionized acetic acid must remain equal to 0.020 M.

0.020 M=[CH3COO−]+[CH3COOH]

For any systematic equilibrium, there might be more than one mass balance equations unlike charge balance equation. Such equations are governed by possible product species.

Answer 8

(b)

Interpretation Introduction

Interpretation:

Mass balance equation for CaF2 in water when additional species HF and HF2− are also formed have to be written.

Concept Introduction:

Refer to part (a).

Answer 9

(b)

Interpretation Introduction

Interpretation:

Mass balance equation for CaF2 in water when additional species HF and HF2− are also formed have to be written.

Concept Introduction:

Refer to part (a).

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 12 - Prob. 12.1P Ch. 12 - Prob. 12.2P Ch. 12 - Prob. 12.3P Ch. 12 - Prob. 12.4P Ch. 12 - Prob. 12.5P Ch. 12 - Prob. 12.6P Ch. 12 - Prob. 12.7P Ch. 12 - Prob. 12.8P Ch. 12 - Prob. 12.9P Ch. 12 - Prob. 12.10P

Interpretation: Mass balance equation for CaF2 in water when additional species HF and HF2− are also formed have to be written. Concept Introduction: Refer to part (a).

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Chapter 12 Solutions

Interpretation:

Mass balance equation for CaF2 in water when additional species HF and HF2− are also formed have to be written.

Concept Introduction:

Refer to part (a).