(a)
Interpretation:
The valence band, conduction band, and band gap should be determined.
Concept introduction:
The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.
(b)
Interpretation:
The electron population change when silicon is doped with gallium should be shown.
Concept introduction:
The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.
(c)
Interpretation:
The electron population change when silicon is doped with arsenic should be shown.
Concept introduction:
The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.
(d)
Interpretation:
The electrical conductivity of doped silicon semiconductor with pure silicon should be compared.
Concept introduction:
The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher
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Chapter 12 Solutions
Chemistry, Loose-leaf Edition (8th Edition)
- Select the stronger base from each pair of compounds. (a) H₂CNH₂ or EtzN (b) CI or NH2 NH2 (c) .Q or EtzN (d) or (e) N or (f) H or Harrow_forward4. Provide a clear arrow-pushing mechanism for each of the following reactions. Do not skip proton transfers, do not combine steps, and make sure your arrows are clear enough to be interpreted without ambiguity. a. 2. 1. LDA 3. H3O+ HOarrow_forwardb. H3C CH3 H3O+ ✓ H OHarrow_forward
- 2. Provide reagents/conditions to accomplish the following syntheses. More than one step is required in some cases. a. CH3arrow_forwardIdentify and provide an explanation that distinguishes a qualitative and quantitative chemical analysis. Provide examples.arrow_forwardIdentify and provide an explanation of the operational principles behind a Atomic Absorption Spectrometer (AAS). List the steps involved.arrow_forward
- Instructions: Complete the questions in the space provided. Show all your work 1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l) Initial rate Trial [BrO3] [H*] [Br] (mol/L) (mol/L) | (mol/L) (mol/L.s) 1 0.10 0.10 0.10 8.0 2 0.20 0.10 0.10 16 3 0.10 0.20 0.10 16 4 0.10 0.10 0.20 32 a. Based on the above data what is the rate law expression? b. Solve for the value of k (make sure to include proper units) 2. The proposed reaction mechanism is as follows: i. ii. BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq) HBrO³ (aq) + H* (aq) → H₂BrO3* (aq) iii. H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l) [Fast] [Medium] [Slow] iv. Br₂O₂ (aq) + 4H*(aq) + 4Br(aq) → 3Br₂ (l) + H2O (l) [Fast] Evaluate the validity of this proposed reaction. Justify your answer.arrow_forwardе. Д CH3 D*, D20arrow_forwardC. NaOMe, Br Brarrow_forward
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