
Concept explainers
(a)
Interpretation:
The picture of bands that depicts highest melting point should be determined.
Concept introduction:
The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.
(b)
Interpretation:
The picture of bands that depicts lowest melting point should be determined.
Concept introduction:
The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.
(c)
Interpretation:
The increasing order band picture with respect to hardness should be determined.
Concept introduction:
The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.

Want to see the full answer?
Check out a sample textbook solution
Chapter 12 Solutions
Chemistry, Loose-leaf Edition (8th Edition)
- handwritten answer please!arrow_forwardConsider the following SN 2 reaction: مار + Br H₂O acetone + Br OH What effect would each of the following changes have on the rate of this reaction. Select the single best answer for each part. Part 1 of 3 If the substrate was changed to: The rate would Br O increase O decrease O remain unchanged Part 2 of 3 × S If the nucleophile was changed to OH, the rate would: O increase O decrease O remain unchanged Part 3 of 3 If the solvent was changed to ethanol, the rate would: Increase O decrease O remain unchanged 2 ol Ararrow_forwardConsider the following nucleophilic substitution reaction. The compound listed above the arrow is the solvent for the reaction. If nothing is listed over the arrow, then the nucleophile is also the solvent for the reaction. Part: 0/2 Part 1 of 2 Br acetone + I What is the correct mechanism for the reaction? Select the single best answer. OSN 1 OSN 2 X Part: 1/2 Part 2 of 2 Draw the products for the reaction. Include both the major organic product and the inorganic product. If more than one stereoisomer is possible, draw only one stereoisomer. Include stereochemistry where relevant. Click and drag to start drawing a structure. Х 5 ☐arrow_forward
- Triethyloxonium tetrafluoroborate reacts with ethanol (CH3CH2OH) to give diethyl ether (CH3CH2OCH2CH3). BF triethyloxonium tetrafluoroborate Which equation, including the curved arrows, best represents the rate-determining step in the mechanism? Select the single best answer. O OH CH3CH2 OH + H. 0+ CH₂H₂ :0 + 0+ ж + H + :0: 0 Carrow_forwardCH3CH2CH=CH2 + H₂O − H+arrow_forwardГ C-RSA CHROMATOPAC CH=1 DATA 1: @CHRM1.C00 ATTEN=10 SPEED= 10.0 0.0 b.092 0.797 1.088 1.813 C-RSA CHROMATOPAC CH=1 Report No. =13 ** CALCULATION REPORT ** DATA=1: @CHRM1.000 11/03/05 08:09:52 CH PKNO TIME 1 2 0.797 3 1.088 4 1.813 AREA 1508566 4625442 2180060 HEIGHT 207739 701206 V 287554 V MK IDNO CONC NAME 18.1447 55.6339 26.2213 TOTAL 8314067 1196500 100 C-R8A CHROMATOPAC CH=1 DATA 1: @CHRM1.C00 ATTEN=10 SPEED= 10.0 0. 0 087 337. 0.841 1.150 C-R8A CHROMATOPAC CH=1 Report No. =14 DATA=1: @CHRM1.000 11/03/05 08:12:40 ** CALCULATION REPORT ** CH PKNO TIME AREA 1 3 0.841 1099933 41.15 4039778 HEIGHT MK IDNO 170372 649997¯¯¯ CONC NAME 21.4007 78.5993 TOTAL 5139711 820369 100 3 C-R8A CHROMATOPAC CH=1 DATA 1: @CHRM1.C00 ATTEN=10 SPEED= 10.0 0.100 0:652 5.856 3 1.165 C-RSA CHROMATOPAC CH-1 Report No. =15 DATA=1: @CHRM1.000 11/03/05 08:15:26 ** CALCULATION REPORT ** CH PKNO TIME AREA HEIGHT MK IDNO CONC NAME 1 3 3 0.856 4 1.165 TOTAL 1253386 4838738 175481 708024 V 20.5739 79.4261 6092124…arrow_forward
- break down both reactions shown and explain it correctly using the bromonium ion mechanism, instead of the (disproven) carbocation-based mechanism.arrow_forwardIndicate how from 1,2-diaminobenzene to obtain 1-metilbenzotriazol.arrow_forward-C = C - C - + Br₂ + I" -> -C-C-c -C = C -C- + Br² + I₂ -C=C Br I + Brū + Iz -7- C - C-C- I Br Mechanism; - C = c - c - + Br - Br > - C-c-c- Br -C-C-C- + 1 - - -Ċ-Ċ'-c' - Br Br Iarrow_forward
- Principles of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
- Chemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStax



