LCPO CHEMISTRY W/MODIFIED MASTERING
LCPO CHEMISTRY W/MODIFIED MASTERING
8th Edition
ISBN: 9780135214756
Author: Robinson
Publisher: PEARSON
Question
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Chapter 12, Problem 12.142MP
Interpretation Introduction

(a)

Interpretation:

The three dimensional structure of one unit cell of the alkali metal fulleride superconductor M3C60 needs to be drawn.

Concept introduction:

Unit cell is defined as the smaller group of atoms having overall crystal symmetry from which one can build the whole lattice in repetition order in 3D form.

Interpretation Introduction

(b)

Interpretation:

The number of C603 ions, octahedral holes and tetrahedral holes present in 1 unit cell needs to be determined.

Concept introduction:

The shape of the tetrahedral holes is triangular. When 2 tetrahedral holes combine from different layers, an octahedral hole is formed. Thus, due to alignment of tetrahedral holes of first and second order align together, an octahedral hole is formed.

Interpretation Introduction

(c)

Interpretation:

The fractional coordinates needs to be determined for all the octahedral and tetrahedral holes in the unit cell.

Concept introduction:

Fractional coordinates are defined as fractions of edge length of the unit cell. For example, at the center of the cell, the fractional coordinate of a hole is (12,12,12).

Interpretation Introduction

(d)

Interpretation:

The radii of the octahedral and tetrahedral holes needs to be calculated assuming the C603 ions are in contact in the unit cell along a face diagonal and radius of the C603 anion is 500 pm.

Concept introduction:

The face diagonal in the unit cell can be represented as follows:

LCPO CHEMISTRY W/MODIFIED MASTERING, Chapter 12, Problem 12.142MP , additional homework tip  1

The length of a face diagonal is 2a. Here, a is face length of the cube. The relation between radius of sphere R and face diagonal is as follows:

2R=2a

Now, along the body diagonal there are 2 spheres touching the tetrahedral holes of radius r thus,

2R+2rt=3a

Here, rt is radius of the tetrahedral hole.

Or,

2R+2rt=3a2R+2rt=3(2R 2 )

On rearranging,

rt=0.225R

Here, R is radius of the sphere.

Similarly, an octahedral hole can be represented as follows:

LCPO CHEMISTRY W/MODIFIED MASTERING, Chapter 12, Problem 12.142MP , additional homework tip  2

Here, radius of sphere is R and that of an octahedral hole is ro. Pythagoras theorem can be used here as follows:

(R+ro)2+(R+ro)2=(2R)2

Or,

2(R+ro)2=2R2

Or,

R+ro=2Rro=2RRro=0.414R

Here, R is radius of the sphere.

Interpretation Introduction

(e)

Interpretation:

The ion from the given ions that will fit into the octahedral and tetrahedral holes needs to be determined. The ion that will only fit if the framework of C603 ions expands needs to be determined.

Concept introduction:

The shape of the tetrahedral holes is triangular. When 2 tetrahedral holes combine from different layers, an octahedral hole is formed. Thus, due to alignment of tetrahedral holes of first and second order align together, an octahedral hole is formed.

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Chapter 12 Solutions

LCPO CHEMISTRY W/MODIFIED MASTERING

Ch. 12 - Prob. 12.11PCh. 12 - Prob. 12.12ACh. 12 - Prob. 12.13PCh. 12 - Prob. 12.14PCh. 12 - Prob. 12.15PCh. 12 - Prob. 12.16PCh. 12 - Prob. 12.17PCh. 12 - Identify each of the following kinds of packingCh. 12 - Prob. 12.19CPCh. 12 - Titanium oxide crystallizes in the following cubic...Ch. 12 - Prob. 12.21CPCh. 12 - Prob. 12.22CPCh. 12 - Prob. 12.23CPCh. 12 - Prob. 12.24CPCh. 12 - Prob. 12.25CPCh. 12 - Prob. 12.26SPCh. 12 - Prob. 12.27SPCh. 12 - Prob. 12.28SPCh. 12 - Prob. 12.29SPCh. 12 - Prob. 12.30SPCh. 12 - Prob. 12.31SPCh. 12 - Diffraction of X rays with =154.2 pm at an angle...Ch. 12 - Diffraction of X rays with =154.2 pm at an angle...Ch. 12 - Which of the four kinds of packing used by metals...Ch. 12 - What is a unit cell? How many atoms are in one...Ch. 12 - Copper crystallizes in a face-centered cubic unit...Ch. 12 - Lead crystallizes in a cubic unit cell with anedge...Ch. 12 - Prob. 12.38SPCh. 12 - Tungsten crystallizes in a body-centered cubic...Ch. 12 - Prob. 12.40SPCh. 12 - Prob. 12.41SPCh. 12 - Titanium metal has a density of and an atomic...Ch. 12 - Calcium metal has a density of 1.55 g/cm3 and...Ch. 12 - The atomic radius of Pb is 175 pm, and the density...Ch. 12 - The density of a sample of metal was measured to...Ch. 12 - If a protein can be induced to crystallize, its...Ch. 12 - The molecular structure of a scorpion toxin, a...Ch. 12 - Iron crystallizes in a body-centered cubic unit...Ch. 12 - Silver metal crystallizes in a face-centered cubic...Ch. 12 - Sodium hydride, NaH, crystallizes in a...Ch. 12 - Cesium chloride crystallizers in a cubic unit cell...Ch. 12 - If the edge length of an NaH unit cell is 488 pm,...Ch. 12 - The edge length of a CsCI unit cell (Problem...Ch. 12 - Silicon carbide, SiC, is a covalent network solid...Ch. 12 - Prob. 12.55SPCh. 12 - Prob. 12.56SPCh. 12 - Prob. 12.57SPCh. 12 - Prob. 12.58SPCh. 12 - Prob. 12.59SPCh. 12 - Prob. 12.60SPCh. 12 - Prob. 12.61SPCh. 12 - Prob. 12.62SPCh. 12 - Prob. 12.63SPCh. 12 - Prob. 12.64SPCh. 12 - Prob. 12.65SPCh. 12 - Prob. 12.66SPCh. 12 - Prob. 12.67SPCh. 12 - Prob. 12.68SPCh. 12 - Prob. 12.69SPCh. 12 - Prob. 12.70SPCh. 12 - Prob. 12.71SPCh. 12 - Prob. 12.72SPCh. 12 - Prob. 12.73SPCh. 12 - Prob. 12.74SPCh. 12 - Prob. 12.75SPCh. 12 - Prob. 12.76SPCh. 12 - Prob. 12.77SPCh. 12 - Prob. 12.78SPCh. 12 - Prob. 12.79SPCh. 12 - Prob. 12.80SPCh. 12 - Prob. 12.81SPCh. 12 - Prob. 12.82SPCh. 12 - Prob. 12.83SPCh. 12 - Prob. 12.84SPCh. 12 - Prob. 12.85SPCh. 12 - Prob. 12.86SPCh. 12 - Prob. 12.87SPCh. 12 - Prob. 12.88SPCh. 12 - Prob. 12.89SPCh. 12 - Prob. 12.90SPCh. 12 - Prob. 12.91SPCh. 12 - Prob. 12.92SPCh. 12 - Prob. 12.93SPCh. 12 - Prob. 12.94SPCh. 12 - Prob. 12.95SPCh. 12 - Prob. 12.96SPCh. 12 - Prob. 12.97SPCh. 12 - Prob. 12.98SPCh. 12 - Prob. 12.99SPCh. 12 - Prob. 12.100SPCh. 12 - Prob. 12.101SPCh. 12 - A photovoltaic cell contains a p-n junction that...Ch. 12 - Prob. 12.103SPCh. 12 - Prob. 12.104SPCh. 12 - Prob. 12.105SPCh. 12 - Prob. 12.106SPCh. 12 - Prob. 12.107SPCh. 12 - Prob. 12.108SPCh. 12 - Prob. 12.109SPCh. 12 - Prob. 12.110SPCh. 12 - Prob. 12.111SPCh. 12 - Prob. 12.112SPCh. 12 - Prob. 12.113SPCh. 12 - Prob. 12.114SPCh. 12 - Prob. 12.115SPCh. 12 - Prob. 12.116SPCh. 12 - Prob. 12.117SPCh. 12 - Prob. 12.118SPCh. 12 - Prob. 12.119SPCh. 12 - Prob. 12.120SPCh. 12 - Prob. 12.121SPCh. 12 - Prob. 12.122SPCh. 12 - Prob. 12.123SPCh. 12 - Prob. 12.124SPCh. 12 - Prob. 12.125SPCh. 12 - Prob. 12.126SPCh. 12 - Prob. 12.127SPCh. 12 - Prob. 12.128SPCh. 12 - Prob. 12.129SPCh. 12 - Prob. 12.130SPCh. 12 - Prob. 12.131SPCh. 12 - Prob. 12.132SPCh. 12 - Prob. 12.133SPCh. 12 - Prob. 12.134MPCh. 12 - Prob. 12.135MPCh. 12 - Prob. 12.136MPCh. 12 - Prob. 12.137MPCh. 12 - Assume that 1588 g of an alkali metal undergoes...Ch. 12 - Prob. 12.139MPCh. 12 - Prob. 12.140MPCh. 12 - Prob. 12.141MPCh. 12 - Prob. 12.142MPCh. 12 - Prob. 12.143MPCh. 12 - Prob. 12.144MP
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