(a)
Interpretation:
The three dimensional structure of one unit cell of the alkali metal fulleride superconductor
Concept introduction:
Unit cell is defined as the smaller group of atoms having overall crystal symmetry from which one can build the whole lattice in repetition order in 3D form.
(b)
Interpretation:
The number of
Concept introduction:
The shape of the tetrahedral holes is triangular. When 2 tetrahedral holes combine from different layers, an octahedral hole is formed. Thus, due to alignment of tetrahedral holes of first and second order align together, an octahedral hole is formed.
(c)
Interpretation:
The fractional coordinates needs to be determined for all the octahedral and tetrahedral holes in the unit cell.
Concept introduction:
Fractional coordinates are defined as fractions of edge length of the unit cell. For example, at the center of the cell, the fractional coordinate of a hole is
(d)
Interpretation:
The radii of the octahedral and tetrahedral holes needs to be calculated assuming the
Concept introduction:
The face diagonal in the unit cell can be represented as follows:
The length of a face diagonal is
Now, along the body diagonal there are 2 spheres touching the tetrahedral holes of radius r thus,
Here, rt is radius of the tetrahedral hole.
Or,
On rearranging,
Here, R is radius of the sphere.
Similarly, an octahedral hole can be represented as follows:
Here, radius of sphere is R and that of an octahedral hole is
Or,
Or,
Here, R is radius of the sphere.
(e)
Interpretation:
The ion from the given ions that will fit into the octahedral and tetrahedral holes needs to be determined. The ion that will only fit if the framework of
Concept introduction:
The shape of the tetrahedral holes is triangular. When 2 tetrahedral holes combine from different layers, an octahedral hole is formed. Thus, due to alignment of tetrahedral holes of first and second order align together, an octahedral hole is formed.
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Chapter 12 Solutions
LCPO CHEMISTRY W/MODIFIED MASTERING
- Provide steps and explanation please.arrow_forwardDraw a structural formula for the major product of the acid-base reaction shown. H 0 N + HCI (1 mole) CH3 N' (1 mole) CH3 You do not have to consider stereochemistry. ● • Do not include counter-ions, e.g., Na+, I, in your answer. . In those cases in which there are two reactants, draw only the product from 989 CH3 344 ? [Farrow_forwardQuestion 15 What is the major neutral organic product for the following sequence? 1. POCI₂ pyridine ? 2. OsO4 OH 3. NaHSO Major Organic Product ✓ OH OH 'OH OH 'OH 'CIarrow_forward
- Could you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but (color-coded) and step by step so I can understand it better? Thank you! I want to see what they are doingarrow_forward
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