(a) Interpretation: A representation depicting the initial mixture of N 2 and H 2 gases and a concentration profile representing the reaction of the stated gases to form ammonia is given. The questions based on the given data are to be answered. Concept introduction: The state when the reactants involved in a chemical reaction and the products formed in the reaction exist in concentrations having no further tendency to change is known as an equilibrium state of the reaction. To determine: The labeling of the given terms and an explanation regarding the same.
(a) Interpretation: A representation depicting the initial mixture of N 2 and H 2 gases and a concentration profile representing the reaction of the stated gases to form ammonia is given. The questions based on the given data are to be answered. Concept introduction: The state when the reactants involved in a chemical reaction and the products formed in the reaction exist in concentrations having no further tendency to change is known as an equilibrium state of the reaction. To determine: The labeling of the given terms and an explanation regarding the same.
Solution Summary: The author explains the equilibrium state of a chemical reaction and the concentration profile of the stated gases to form ammonia.
Definition Definition Transformation of a chemical species into another chemical species. A chemical reaction consists of breaking existing bonds and forming new ones by changing the position of electrons. These reactions are best explained using a chemical equation.
Chapter 12, Problem 10Q
Interpretation Introduction
(a)
Interpretation: A representation depicting the initial mixture of
N2 and
H2 gases and a concentration profile representing the reaction of the stated gases to form ammonia is given. The questions based on the given data are to be answered.
Concept introduction: The state when the reactants involved in a chemical reaction and the products formed in the reaction exist in concentrations having no further tendency to change is known as an equilibrium state of the reaction.
To determine: The labeling of the given terms and an explanation regarding the same.
Interpretation Introduction
(b)
Interpretation: A representation depicting the initial mixture of
N2 and
H2 gases and a concentration profile representing the reaction of the stated gases to form ammonia is given. The questions based on the given data are to be answered.
Concept introduction: The state when the reactants involved in a chemical reaction and the products formed in the reaction exist in concentrations having no further tendency to change is known as an equilibrium state of the reaction.
To determine: An explanation regarding the relative shapes of the given plot.
Interpretation Introduction
(c)
Interpretation: A representation depicting the initial mixture of
N2 and
H2 gases and a concentration profile representing the reaction of the stated gases to form ammonia is given. The questions based on the given data are to be answered.
Concept introduction: The state when the reactants involved in a chemical reaction and the products formed in the reaction exist in concentrations having no further tendency to change is known as an equilibrium state of the reaction.
To determine: The point when the equilibrium state is reached.
JON
Determine the bund energy for
UCI (in kJ/mol Hcl) using me
balanced chemical equation and
bund energies listed?
का
(My (9) +36/2(g)-(((3(g) + 3(g)
A Hryn = -330. KJ
bond energy
и-н 432
bond
bond
C-1413
C=C 839 N-H
391
C=O 1010
S-H 363
б-н 467
02 498
N-N
160
N=N
243
418
C-C 341
C-0 358
C=C
C-C 339 N-Br
243
Br-Br
C-Br 274
193
614
(-1 214||(=olin (02) 799
C=N
615
AAL
Determine the bond energy for HCI (
in kJ/mol HCI) using he balanced
cremiculequecticnand bund energles
listed? also c double bond to N is
615, read numbets carefully please!!!!
Determine the bund energy for
UCI (in kJ/mol cl) using me
balanced chemical equation and
bund energies listed?
51
(My (9) +312(g)-73(g) + 3(g)
=-330. KJ
спод
bond energy
Hryn
H-H
bond
band
432
C-1 413
C=C 839 NH
391
C=O 1010
S-1 343
6-H
02 498
N-N
160
467
N=N
C-C
341
CL-
243
418
339 N-Br
243
C-O
358
Br-Br
C=C
C-Br 274
193
614
(-1 216 (=olin (02) 799
C=N
618
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