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WebAssign Homework Only for Moaveni's Engineering Fundamentals: An Introduction to Engineering, SI Edition, 6th Edition, [Instant Access]
6th Edition
ISBN: 9780357126677
Author: MOAVENI
Publisher: Cengage Learning US
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Chapter 11.6, Problem 1BYG
To determine
Explain the meaning of degree-day.
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Determine the minimum of the appropriate yellow interval (Y
.
approach speed limit: 45 mi/h
approach grade: 3.2% downgrade
assumed perception-reaction time: 1.0 sec
assumed deceleration rate: 11.2 ft/sec²
assumed average vehicle length: 20 ft
width of intersection to be crossed: 56 ft
min'
in s) for a signal phase under the following conditions.
Compute the nominal shear strength of an M10 × 7.5 of A572 Grade 60 steel (Fy = 60 ksi).
For M10 × 7.5: d = 9.99 in., tw = 0.13 in., h/tw
Vn
=
x
kips
= 71.
A flexural member is fabricated from two flange plates 1/2 × 71/2 and a web plate 3/8 × 20. The yield stress of the steel is 50 ksi.
a. Compute the plastic section modulus Z and the plastic moment Mp with respect to the major principal axis.
(Express your answers to three significant figures.)
Z =
Mp
=
in. 3
ft-kips
b. Compute the elastic section modulus S and the yield moment My with respect to the major principal axis.
(Express your answers to three significant figures.)
S =
My
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ft-kips
Chapter 11 Solutions
WebAssign Homework Only for Moaveni's Engineering Fundamentals: An Introduction to Engineering, SI Edition, 6th Edition, [Instant Access]
Ch. 11.2 - Prob. 1BYGCh. 11.2 - Prob. 2BYGCh. 11.2 - Prob. 3BYGCh. 11.2 - Prob. 4BYGCh. 11.2 - Prob. 5BYGCh. 11.2 - Prob. BYGVCh. 11.4 - Prob. 1BYGCh. 11.4 - Prob. 2BYGCh. 11.4 - Prob. 3BYGCh. 11.4 - Prob. 4BYG
Ch. 11.4 - Prob. BYGVCh. 11.6 - Prob. 1BYGCh. 11.6 - Prob. 2BYGCh. 11.6 - Prob. 3BYGCh. 11.6 - Prob. 4BYGCh. 11.6 - Prob. BYGVCh. 11 - Prob. 1PCh. 11 - Prob. 2PCh. 11 - Alcohol thermometers can measure temperatures in...Ch. 11 - Prob. 4PCh. 11 - Prob. 5PCh. 11 - Prob. 6PCh. 11 - Prob. 7PCh. 11 - Prob. 8PCh. 11 - Calculate the R-value for the following materials:...Ch. 11 - Calculate the thermal resistance due to convection...Ch. 11 - Prob. 11PCh. 11 - Prob. 12PCh. 11 - Prob. 13PCh. 11 - Estimate the change in the length of a power...Ch. 11 - Calculate the change in 5 m long copper wire when...Ch. 11 - Prob. 16PCh. 11 - Prob. 17PCh. 11 - Prob. 19PCh. 11 - Prob. 20PCh. 11 - Prob. 23PCh. 11 - Prob. 24PCh. 11 - Prob. 26PCh. 11 - Prob. 27PCh. 11 - Prob. 28PCh. 11 - Prob. 29PCh. 11 - Prob. 30PCh. 11 - Prob. 31PCh. 11 - Prob. 32PCh. 11 - Prob. 33PCh. 11 - Prob. 34PCh. 11 - Prob. 35PCh. 11 - For Problems 11.11, 11.12, and 11.13, calculate...Ch. 11 - Prob. 37PCh. 11 - Prob. 38PCh. 11 - Prob. 39PCh. 11 - Prob. 40PCh. 11 - Prob. 41PCh. 11 - Prob. 42PCh. 11 - Prob. 43PCh. 11 - Prob. 44PCh. 11 - Prob. 45PCh. 11 - Prob. 46PCh. 11 - Prob. 47PCh. 11 - Prob. 48PCh. 11 - Prob. 49PCh. 11 - Prob. 51PCh. 11 - Prob. 52PCh. 11 - Prob. 53PCh. 11 - Prob. 54PCh. 11 - Prob. 55P
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- A W16×67 of A992 steel has two holes in each flange for 7/8-inch-diameter bolts. For A992 steel: Fy = 50 ksi, F₁ = 65 ksi. For a W16×67: bƒ = 10.2 in., tf = 0.665 in., Zx =130 in.3 and S = 117 in.3 a. Assuming continuous lateral support, verify that the holes must be accounted for and determine the nominal flexural strength. (Express your answer to three significant figures.) Mn = ft-kips b. What is the percent reduction in strength? (Express your answer to three significant figures.) % Reduction =arrow_forwardA gravity retaining wall is shown in the figure below. Calculate the factor of safety with respect to overturning and sliding, given the following data: Wall dimensions: H = 6 m, x1 = 0.6 m, x2 = 2 m, x3 = 2m, x4 = 0.5 m, x5 = 0.75 m, x6 = 0.8 m, D= 1.5 m Soil properties: 1 = 17.5 kN/m³, ø₁ = 32°, 12 = 18 kN/m³, =22°, 40 kN/m² Y₁ H D x2 x3 x5 X6 Use the Rankine active earth pressure in your calculation. Use Yconcrete = 23.58 kN/m³. Also, use k₁ = k₂ = 2/3 and P₁ = 0 in the equation FS S(sliding) | tan(k102) + Bk₂c½ + Pp (Σν). Pa cos a (Enter your answers to three significant figures.) FS (overturning) FS (sliding)arrow_forwardQ4 Use b member Castigliano's second theorem to determine the structure shown Forces In figure below longer than + In IF required. For all members member EC IS 10mm E = 200 KN/mm² 200KN YE FV 100 KN A = 1800 mm² and 2 2m 3m B D 3m 8M *arrow_forward
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- A 7K SK-> VE 3 F T A=52 E=29000 ksi diagonal members 6' A=30.25.72 E=1800 ksi for horizontal & vertical member ↓ B Oc AD 8 Primary Structures remove roller @C make D a roller For Primary and Cut BF For redundant Ik ↑ ec Ik = @D Ik @BFarrow_forwardConsider the geometric and traffic characteristics shown below. Approach (Width) North South East West (56 ft) (56 ft) (68 ft) (68 ft) Peak hour Approach Volumes: Left Turn 165 105 200 166 Through Movement 447 400 590 543 Right Turn 162 157 191 200 Conflicting Pedestrian Volumes 900 1,200 1,200 900 PHF 0.95 0.95 0.95 0.95 For the following saturation flows: Through lanes: 1,600 veh/h/In Through-right lanes: 1,400 veh/h/In Left lanes: 1,000 veh/h/In Left-through lanes: 1,200 veh/h/In Left-through-right lanes: 1,100 veh/h/In The total cycle length was 283 s. Now assume the saturation flow rates are 10% higher, that is, assume the following saturation flow rates: Through lanes: 1,760 veh/h/In Through-right lanes: 1,540 veh/h/In Left lanes: 1,100 veh/h/In Left-through lanes: 1,320 veh/h/In 1,210 veh/h/In Left-through-right lanes: Determine a suitable signal phasing system and phase lengths (in s) for the intersection using the Webster method. (Enter the sum of green and yellow times for…arrow_forwardThe given beam has continuous lateral support. If the live load is twice the dead load, what is the maximum total service load, in kips / ft, that can be supported? A992 steel is used: Fy = 50 ksi, Fu=65 ksi. Take L = 30 ft. bf For W40 x 149: 2tf = 7.11, = = 54.3, Z 598 in.³ tw W W40 X 149 L (Express your answers to three significant figures.) a. Use LRFD. Wtotal = kips/ft b. Use ASD. Wtotal kips/ftarrow_forward
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