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WebAssign Homework Only for Moaveni's Engineering Fundamentals: An Introduction to Engineering, SI Edition, 6th Edition, [Instant Access]
6th Edition
ISBN: 9780357126677
Author: MOAVENI
Publisher: Cengage Learning US
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Chapter 11, Problem 46P
To determine
Find the degree-days for the months of December, January, and February 2018 and compare it to the 2018 annual degree-days value.
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At a point on the surface of a generator shaft the stresses are σx = -55MPa, σy =
25MPa and Txy = -20MPa as shown in Figure Q1.
(a) Using either analytical method or Mohr's circle determine the following:
Stresses acting on an element inclined at an angle 0 = 35°,
i.
ii.
iii.
The maximum shear stress
The principal stresses and
B.
25 MPa
A
55 MPa
20 MPa
Figure 1:Material stress state
(b) Consider that the Young's modulus for the material, E = 200kPa and
Poisson's ratio, v = 0.25.
i.
ii.
determine associate strains for the material with the stress as shown in
Figure 1
determine associate strains for the material with the stress at element
oriented at 35° (question 1a(i))
For an reinforced concrete two-way slab shown in figure under the load (P). (the slab
continuous over all edges - all sides are fixed), Determine (By using yield line theory):
A- Draw the Yield line Pattern
B- Determine the moment m
C- Find The required flexural steel to resist the loads causing the slab to collapse if P = 200
KN, f=28 MPa, fy = 420 MPa d = 120 mm. Use 10 mm bars.
Draw the yield line and
(Qmin = 0.002)
2m
solve
PO
6 m
3 m
-8 m
Find the internal torques for segments AB, BC, and CD (in N-m) by drawing the internal torque diagram, the maximum torsional shear on the shaft in MPa, and the relative rotation of section A with respect to section D in degrees.
Chapter 11 Solutions
WebAssign Homework Only for Moaveni's Engineering Fundamentals: An Introduction to Engineering, SI Edition, 6th Edition, [Instant Access]
Ch. 11.2 - Prob. 1BYGCh. 11.2 - Prob. 2BYGCh. 11.2 - Prob. 3BYGCh. 11.2 - Prob. 4BYGCh. 11.2 - Prob. 5BYGCh. 11.2 - Prob. BYGVCh. 11.4 - Prob. 1BYGCh. 11.4 - Prob. 2BYGCh. 11.4 - Prob. 3BYGCh. 11.4 - Prob. 4BYG
Ch. 11.4 - Prob. BYGVCh. 11.6 - Prob. 1BYGCh. 11.6 - Prob. 2BYGCh. 11.6 - Prob. 3BYGCh. 11.6 - Prob. 4BYGCh. 11.6 - Prob. BYGVCh. 11 - Prob. 1PCh. 11 - Prob. 2PCh. 11 - Alcohol thermometers can measure temperatures in...Ch. 11 - Prob. 4PCh. 11 - Prob. 5PCh. 11 - Prob. 6PCh. 11 - Prob. 7PCh. 11 - Prob. 8PCh. 11 - Calculate the R-value for the following materials:...Ch. 11 - Calculate the thermal resistance due to convection...Ch. 11 - Prob. 11PCh. 11 - Prob. 12PCh. 11 - Prob. 13PCh. 11 - Estimate the change in the length of a power...Ch. 11 - Calculate the change in 5 m long copper wire when...Ch. 11 - Prob. 16PCh. 11 - Prob. 17PCh. 11 - Prob. 19PCh. 11 - Prob. 20PCh. 11 - Prob. 23PCh. 11 - Prob. 24PCh. 11 - Prob. 26PCh. 11 - Prob. 27PCh. 11 - Prob. 28PCh. 11 - Prob. 29PCh. 11 - Prob. 30PCh. 11 - Prob. 31PCh. 11 - Prob. 32PCh. 11 - Prob. 33PCh. 11 - Prob. 34PCh. 11 - Prob. 35PCh. 11 - For Problems 11.11, 11.12, and 11.13, calculate...Ch. 11 - Prob. 37PCh. 11 - Prob. 38PCh. 11 - Prob. 39PCh. 11 - Prob. 40PCh. 11 - Prob. 41PCh. 11 - Prob. 42PCh. 11 - Prob. 43PCh. 11 - Prob. 44PCh. 11 - Prob. 45PCh. 11 - Prob. 46PCh. 11 - Prob. 47PCh. 11 - Prob. 48PCh. 11 - Prob. 49PCh. 11 - Prob. 51PCh. 11 - Prob. 52PCh. 11 - Prob. 53PCh. 11 - Prob. 54PCh. 11 - Prob. 55P
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- A prestressed simply supported 15 m span beam with rectangular box section is post-tensioned by straight high tensile steel wires as shown in Figure. The prestressing wires are placed at the center line of the flanges and initially stressed to 850 N/mm². The beam is required to carry a uniformly distributed superimposed load of 4.5 kN/m in addition to its weight. If the concrete stresses are not to exceed 17 MPa in compression and 1 MPa in tension at service stage, calculate the range of the total prestressing wires area required. Ignore prestressing force losses in your answer. (Ye kN/m³). = 24 2As 400 As 80 80; 750arrow_forwardA simply supported rectangular prestressed concrete beam, of span 13 m and its cross section as shown in figure, is carrying a live load equals to 30 kN/m in addition to its weight, compute the following stresses and compare it with ACI allowable stress: a) Bottom fiber stress at support in initial stage. b) Top fiber stress at mid span in final stage. Use y = 24 kN/m³, As = 600 mm², initial stress of the prestressed steel = 1200 MPa, total losses is 20%, fci = 22 MPa, and fo' = 28 MPa 800 mm 3 As 400 mm As 340 mm 340 mmarrow_forwardA study of the properties of metal plate-connected trusses used for roof support yielded the following observations on axial stiffness index (kips/in.) for plate lengths 4, 6, 8, 10, and 12 in: 4: 320.2 409.5 311.0 326.5 316.8 349.8 309.7 6: 401.1 347.2 361.0 404.5 331.0 348.9 381.7 8: 395.4 366.2 351.0 357.1 409.9 367.3 382.0 10: 356.7 452.9 461.4 433.1 410.6 384.2 362.6 12: 415.4 441.8 419.9 410.7 473.4 441.2 465.8 USE SALT Does variation in plate length have any effect on true average axial stiffness? State the relevant hypotheses using analysis of variance. O Ho M1 M2 M3 = μ4=μ5 Ha all five μ's are unequal Ho: M1 M2 M3 #44 #μ5 Ha all five μ's are equal Ho: M₁ μ2 43 #44 #μ5 H₁: at least two μ,'s are equal O Ho M1 M2 M3 = μ4=μ5 Ha at least two μ's are unequal Test the relevant hypotheses using analysis of variance with a = 0.01. Display your results in an ANOVA table. (Round your answers to two decimal places.) Degrees of Sum of Mean Source Squares Squares f freedom Treatments Error…arrow_forward
- 1-Define a cartesion system 2 identify the structure's supports and the type of structure (2D) or 3D 3-If the structure has more than one element dismember the structure and draw free body diagram(show all actions and reactions) on each element independently 4- Determine the type of suports 5- show the unkown supports reactions with any assumed direction but you cannot change the assumed force direction once you dicede 6-In a common joint, you can dicide on the force direction in one element, however, in the other one you need to follow the Newton'ns 3rd law and shoe the opposite direction 7- if you have multiple actions forces in the system, find force components for each foce independently use Sin/Cos/Tan functions to find forces components in two perpendicular directions 8- Add forces in each direction since they are paralled forces Rx=fx Ry=fy Rz= fyarrow_forwardPhysical properties of six flame-retardant fabric samples were investigated in an article. Use the accompanying data and a 0.05 significance level to determine whether a linear relationship exists between stiffness x (mg-cm) and thickness y (mm). x y 8.08 24.33 12.39 6.99 23.97 35.64 0.25 0.68 0.30 0.28 0.82 0.57 State the appropriate null and alternative hypotheses. ○ Ho: p = 0 H₂: pO ○ Hop = 0 Hap #0 Compute the value of the sample correlation coefficient, r. Round your answer to four decimal places. Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.) P-value = State the conclusion in the problem context. O Fail to reject Ho. The data indicates that the population correlation coefficient differs from 0. Fail to reject Ho. The data does not indicate that the population correlation coefficient differs from 0. Reject Ho. The data indicates that the population correlation coefficient differs…arrow_forward1-Define a cartesion system 2 identify the structure's supports and the type of structure (2D) or 3D 3-If the structure has more than one element dismember the structure and draw free body diagram(show all actions and reactions) on each element independently 4- Determine the type of suports 5- show the unkown supports reactions with any assumed direction but you cannot change the assumed force direction once you dicede 6-In a common joint, you can dicide on the force direction in one element, however, in the other one you need to follow the Newton'ns 3rd law and shoe the opposite direction 7- if you have multiple actions forces in the system, find force components for each foce independently use Sin/Cos/Tan functions to find forces components in two perpendicular directions 8- Add forces in each direction since they are paralled forces Rx=fx Ry=fy Rz= fyarrow_forward
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