Explanation Theorem used: Suppose the power series is given by ∑ n = 0 ∞ a n ( x − a ) n and let R = lim n → ∞ | a n a n + 1 | . a. If R = 0 , then the series converges only for x = a . b. If 0 < R < ∞ , the series converges for x in the interval ( a − R , a + R ) and diverges for x outside the interval [ a − R , a + R ] . c. If R = ∞ , the series converges for all x. Calculation: The given power series is ∑ n = 1 ∞ ( − 1 ) n + 1 ( x − 2 ) n n 2 n . Here, a n = ( − 1 ) n + 1 n 2 n . By using the above mentioned theorem, the radius of convergence of the power series ∑ n = 1 ∞ ( − 1 ) n + 1 ( x − 2 ) n n 2 n is R = lim n → ∞ | ( − 1 ) n + 1 n 2 n ( − 1 ) n + 2 ( n + 1 ) 2 n + 1 | . Solve R = lim n → ∞ | ( − 1 ) n + 1 n 2 n ( − 1 ) n + 2 ( n + 1 ) 2 n + 1 | as follows. R = lim n → ∞ | ( − 1 ) n + 1 n 2 n ( − 1 ) n + 2 ( n + 1 ) 2 n + 1 | = lim n → ∞ | ( − 1 ) n + 1 n 2 n

Applied Calculus for the Managerial, Life, and Social Sciences

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ISBN: 9781305887831

Author: Tan

Publisher: CENGAGE CO

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Chapter 11.5, Problem 20E

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To find: The radius of convergence and the interval of convergence of the power series ∑n=1∞(−1)n+1(x−2)nn2n.

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Chapter 11.5, Problem 19E

Chapter 11.5, Problem 21E

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Applied Calculus for the Managerial, Life, and Social Sciences

Ch. 11.1 - Prob. 1CQ Ch. 11.1 - Prob. 2CQ Ch. 11.1 - Prob. 1E Ch. 11.1 - In Exercises 110, find the first three Taylor...Ch. 11.1 - Prob. 3E Ch. 11.1 - Prob. 4E Ch. 11.1 - Prob. 5E Ch. 11.1 - Prob. 6E Ch. 11.1 - Prob. 7E Ch. 11.1 - Prob. 8E

Ch. 11.1 - In Exercises 110, find the first three Taylor...Ch. 11.1 - Prob. 10E Ch. 11.1 - Prob. 11E Ch. 11.1 - Prob. 12E Ch. 11.1 - Prob. 13E Ch. 11.1 - Prob. 14E Ch. 11.1 - In Exercises 1120, find the nth Taylor polynomial...Ch. 11.1 - Prob. 16E Ch. 11.1 - Prob. 17E Ch. 11.1 - Prob. 18E Ch. 11.1 - Prob. 19E Ch. 11.1 - Prob. 20E Ch. 11.1 - Prob. 21E Ch. 11.1 - Prob. 22E Ch. 11.1 - Prob. 23E Ch. 11.1 - Prob. 24E Ch. 11.1 - Prob. 25E Ch. 11.1 - Prob. 26E Ch. 11.1 - Prob. 27E Ch. 11.1 - Prob. 28E Ch. 11.1 - Prob. 29E Ch. 11.1 - Prob. 30E Ch. 11.1 - Prob. 31E Ch. 11.1 - Prob. 32E Ch. 11.1 - Prob. 33E Ch. 11.1 - Prob. 34E Ch. 11.1 - Let f(x) = ex. a. 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The radius of convergence and the interval of convergence of the power series ∑ n = 1 ∞ ( − 1 ) n + 1 ( x − 2 ) n n 2 n .

Solution Summary: The author calculates the radius and interval of convergence of the given power series.

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To find: The radius of convergence and the interval of convergence of the power series ∑n=1∞(−1)n+1(x−2)nn2n.

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Chapter 11 Solutions