Chapter 11.2, Problem 4LC

Solution

To find the theoretical probability.

Probability is $\frac{1}{3}$ .

Given information:

  $P\left(2\text{ or }4\right)$

Concept:

Let $n$ be the total sample space in which there are equally likely outcomes.

  $A$ occurs in $m$

of the total sample space, then the probability is:

  $P\left(A\right)=\frac{m}{n}$

Calculation:

From the definition above,

  $m=2$ (As 2 and 4 are the favorable event )

Total outcomes are 6.

Hence probability is,

  $\begin{array}{c}P\left(2\text{ or }4\right)=\frac{2}{6}\\ P\left(2\text{ or }4\right)=\frac{1}{3}\end{array}$

Conclusion:

Hence, probability is $\frac{1}{3}$ .