Chapter 11.2, Problem 28E

To determine

To Find: The translation $(x,y)$ in reflection $y=x.$

Answer to Problem 28E

  $(x,y)=(x+3,y+3)$

Explanation of Solution

Given:

  

Reflection: $y=x.$

Thus

  $A(x,y)=A(3,2)=A\text{'}(2,3)$

Now translation

  $\begin{array}{l}A\text{'}(2,3)\to A\text{'}\text{'}(5,6)\\ comparing\\ (x,y)=(x+3,y+3)\end{array}$

Hence,

  $(x,y)=(x+3,y+3)$