Explanation Boyle’s law: According to Boyle’s law; in the condition of constant temperature and constant mol of gas, the volume of the gas is inversely proportional to the pressure of gas. The relation between volume and pressure is expressed as follows: V ∝ 1 P Here, P is the pressure of gas and V is volume of gas. In general; in the condition of constant temperature and constant mol of gas the product of gas pressure and volume is constant, which can be expressed as follows: P V = constant [ T , n fixed ] In other way we can say as , in the condition of constant temperature and constant mol of gas; if the pressure of gas increases then the volume of gas decreases or if the volume of gas decreases then the pressure of gas increases automatically. V ∝ 1 P Calculation: a. According to Boyle’s law: P 1 P 2 = V 2 V 1 Here initial pressure is 655 mmHg, initial volume is 10.0-L, and final volume 20.0 L and now calculate the final pressure as follows: P 1 P 2 = V 2 V 1 P 2 = V 1 V 2 × P 1 = 10 .0 L 20 .0 L × 655 mmHg = 327 .5 mmHg b. Now, According to Boyle’s law: P 1 P 2 = V 2 V 1 Here initial pressure is 655 mmHg, initial volume is 10.0-L, and final volume 2.50 L and now calculate the final pressure as follows: P 1 P 2 = V 2 V 1 P 2 = V 1 V 2 × P 1 = 10

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ISBN: 9780134878119

Author: Timberlake, Karen C. , William

Publisher: Pearson,

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Chapter 11.2, Problem 15PP

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To determine: The changes in the pressure of helium gas when this gas is placed in tanks that have the given volumes.

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Chapter 11.2, Problem 14PP

Chapter 11.2, Problem 16PP

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Chapter 11 Solutions

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The changes in the pressure of helium gas when this gas is placed in tanks that have the given volumes.

Solution Summary: The author explains Boyle's law: in the condition of constant temperature and constant mol of gas, the volume of the gas is inversely proportional to the pressure.

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To determine: The changes in the pressure of helium gas when this gas is placed in tanks that have the given volumes.

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Chapter 11 Solutions