(a)
Interpretation:
Condensed formula and line formula for 1-bromo-3-hexyne has to be drawn.
Concept Introduction:
Organic compounds can be drawn from its IUPAC name. Initially, the parent chain is identified from the IUPAC name. After that the carbon chain is drawn with carbon atoms alone. Next step is to add the substituents in the respective positions as indicated in the IUPAC name. Remaining valency of carbon atom is satisfied by adding correct number of hydrogen atoms.
Condensed structural formula is a simplified form of representation of a molecule. This gives the information about all the atoms present in molecule and the atoms are placed in sequential order which gives information about which atom is bonded to other atom.
Line formula is the simplest representation of molecule. Carbon atoms are not explicitly shown in line formula. Intersection of lines and the end point of line are considered as carbon atoms. At the end-point it is understood as methyl group. Heteroatoms and hydrogen bonded to the heteroatoms are shown explicitly.
(b)
Interpretation:
Condensed formula and line formula for dichloroethyne has to be drawn.
Concept Introduction:
Refer part (a).
(c)
Interpretation:
Condensed formula and line formula for 2-butyne has to be drawn.
Concept Introduction:
Refer part (a).
(d)
Interpretation:
Condensed formula and line formula for 9-iodo-1-nonyne has to be drawn.
Concept Introduction:
Refer part (a).

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Chapter 11 Solutions
GENERAL,ORGANIC,+BIOCHEMISTRY(LL)-PKG
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- Organic Functional Groups entifying positions labeled with Greek letters in acids and derivatives 1/5 ssible, replace an H atom on the a carbon of the molecule in the drawing area with a ce an H atom on the ẞ carbon with a hydroxyl group substituent. ne of the substituents can't be added for any reason, just don't add it. If neither substi er the drawing area. O H OH Oneither substituent can be added. Check D 1 Accessibility ado na witharrow_forwardDifferentiate between electrophilic and nucleophilic groups. Give examples.arrow_forwardAn aldehyde/ketone plus an alcohol gives a hemiacetal, and an excess of alcohol gives an acetal. The reaction is an equilibrium; in aldehydes, it's shifted to the right and in ketones, to the left. Explain.arrow_forward
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