The difference should be explained when the isopropyl trimethyl ammonium hydroxide ion is heated with hydroxide ion and 2-bromopropane is heated with hydroxide ion. Concept introduction: Hofmann elimination: Quaternary ammonium ion undergoes elimination with strong base like hydroxide ion, this reaction is called as Hofmann elimination. In this reaction, the abstraction of proton form β- carbon, which is having more number of hydrogen to produce the alkene .

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Answer 1

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Chapter 11.10, Problem 41P

Interpretation Introduction

Interpretation:

The difference should be explained when the isopropyl trimethyl ammonium hydroxide ion is heated with hydroxide ion and 2-bromopropane is heated with hydroxide ion.

Concept introduction:

Hofmann elimination:

Quaternary ammonium ion undergoes elimination with strong base like hydroxide ion, this reaction is called as Hofmann elimination. In this reaction, the abstraction of proton form β- carbon, which is having more number of hydrogen to produce the alkene.

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Answer 2

Question

Chapter 11.10, Problem 41P

Interpretation Introduction

Interpretation:

The difference should be explained when the isopropyl trimethyl ammonium hydroxide ion is heated with hydroxide ion and 2-bromopropane is heated with hydroxide ion.

Concept introduction:

Hofmann elimination:

Quaternary ammonium ion undergoes elimination with strong base like hydroxide ion, this reaction is called as Hofmann elimination. In this reaction, the abstraction of proton form β- carbon, which is having more number of hydrogen to produce the alkene.

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Answer 3

Question

Chapter 11.10, Problem 41P

Interpretation Introduction

Interpretation:

The difference should be explained when the isopropyl trimethyl ammonium hydroxide ion is heated with hydroxide ion and 2-bromopropane is heated with hydroxide ion.

Concept introduction:

Hofmann elimination:

Quaternary ammonium ion undergoes elimination with strong base like hydroxide ion, this reaction is called as Hofmann elimination. In this reaction, the abstraction of proton form β- carbon, which is having more number of hydrogen to produce the alkene.

Expert Solution & Answer

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Answer 4

Question

Chapter 11.10, Problem 41P

Interpretation Introduction

Interpretation:

The difference should be explained when the isopropyl trimethyl ammonium hydroxide ion is heated with hydroxide ion and 2-bromopropane is heated with hydroxide ion.

Concept introduction:

Hofmann elimination:

Quaternary ammonium ion undergoes elimination with strong base like hydroxide ion, this reaction is called as Hofmann elimination. In this reaction, the abstraction of proton form β- carbon, which is having more number of hydrogen to produce the alkene.

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Answer 5

Chapter 11.10, Problem 41P

Interpretation Introduction

Interpretation:

The difference should be explained when the isopropyl trimethyl ammonium hydroxide ion is heated with hydroxide ion and 2-bromopropane is heated with hydroxide ion.

Concept introduction:

Hofmann elimination:

Quaternary ammonium ion undergoes elimination with strong base like hydroxide ion, this reaction is called as Hofmann elimination. In this reaction, the abstraction of proton form β- carbon, which is having more number of hydrogen to produce the alkene.

Answer 6

Chapter 11.10, Problem 41P

Interpretation Introduction

Interpretation:

The difference should be explained when the isopropyl trimethyl ammonium hydroxide ion is heated with hydroxide ion and 2-bromopropane is heated with hydroxide ion.

Concept introduction:

Hofmann elimination:

Quaternary ammonium ion undergoes elimination with strong base like hydroxide ion, this reaction is called as Hofmann elimination. In this reaction, the abstraction of proton form β- carbon, which is having more number of hydrogen to produce the alkene.

Answer 7

Chapter 11.10, Problem 41P

Interpretation Introduction

Interpretation:

The difference should be explained when the isopropyl trimethyl ammonium hydroxide ion is heated with hydroxide ion and 2-bromopropane is heated with hydroxide ion.

Concept introduction:

Hofmann elimination:

Quaternary ammonium ion undergoes elimination with strong base like hydroxide ion, this reaction is called as Hofmann elimination. In this reaction, the abstraction of proton form β- carbon, which is having more number of hydrogen to produce the alkene.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 11.1 - Why are NH3 and CH3NH2 no longer nucleophiles when...Ch. 11.1 - Prob. 2P Ch. 11.1 - Prob. 5P Ch. 11.2 - Prob. 7P Ch. 11.3 - Prob. 9P Ch. 11.3 - Show how 1-propanol can be converted into the...Ch. 11.4 - Which of the following alcohols dehydrates the...Ch. 11.4 - Prob. 12P Ch. 11.4 - Prob. 13P Ch. 11.4 - Propose a mechanism for each of the following...

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